每第n个字符在起始字符上迭代时分割python字符串 [英] Split python string every nth character iterating over starting character

问题描述

我正在尝试找到一种优雅的方法来在每n个字符中分割一个python字符串，并迭代以哪个字符开头.

I'm trying to find an elegant way to split a python string every nth character, iterating over which character to start with.

例如，假设我有一个包含以下内容的字符串:

For example, suppose I have a string containing the following:

ANDTLGY

我想将字符串分成3个字符，如下所示:

I want to split the string into a set of 3 characters looking like this:

['AND','NDT','DTL','TLG','LGY']

推荐答案

a='ANDTLGY'
def nlength_parts(a,n):
    return map(''.join,zip(*[a[i:] for i in range(n)]))

print nlength_parts(a,3)

希望您可以向教授解释它是如何工作的；)

hopefully you can explain to the professor how it works ;)

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