在Matlab中绘制循环结果 [英] Plotting a result from a loop in matlab

问题描述

我有一个关于在Matlab中绘制循环结果的问题.这是代码.

I have a question about plotting a result from a loop in Matlab. Here is the code.

for t=0:1:10;
  VS=3*exp(-t/3)*sin(pi*t);
  if VS>0
     VL=VS
  else VL=0

  end

end

plot(t,VL)
xlabel('Time(s)')
ylabel('Across Voltage(V)')
title('Across Voltage Vs Time') 

我想根据上述表达式中的电压与从0到10的时间之间的关系绘制一个图.但是，在运行代码后，该图仍然没有显示任何内容.谁能帮我找出原因?

I wanna plot a figure based on the voltage from the above expression versus the time through 0 to 10. However, the figure keeps showing nothing after running the code. Can anyone help me figure out why?

推荐答案

这是因为您正在绘制for循环之外的图形.因此，在那个时候，t不是您期望的向量，而是标量值t=10.另外，VL取决于执行情况.因此，您应该将t形成为向量，并执行以下操作:

This is because you are plotting outside the for loop. So at that time t is not a vector as you expect, its a scalar value, t=10. Also, VL depends on the execution. So you should form t as a vector and do the following:

k=0;
for t=0:1:10;
k=k+1;
  VS=3*exp(-t/3)*sin(pi*t);
  if VS>0
    VL(k,1)=VS
  else VL(k,1)=0
  end
end
plot(0:10,VL)
xlabel('Time(s)')
ylabel('Across Voltage(V)')
title('Across Voltage Vs Time')

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