如何使用循环显示最大和最小数字? [英] What do I have to do to display the largest and the smallest number using a loop?

问题描述

我不知道用户输入-1后如何显示最大和最小的数字.

注意:我还必须显示所有此数字的总和以及该总和的平均值.

到目前为止，这是我的代码:

public static void main(String[] args) {
    // store
    int cnt = 0;
    int acumulator = 0;
    int larger = 0;
    int smaller = 0;
    int number;
    // inputs
    System.out.println("enter the number all the number");
    Scanner kb = new Scanner(System.in);
    number = kb.nextInt();
    // loop
    while (number != -1) {
        acumulator += number;
        number = kb.nextInt();
        cnt++;//
    }
    double average = (acumulator / cnt);
    System.out.println(" The total of your number is=" + acumulator);
    System.out.println(" The average of your number is=" + average);
}

解决方案

好像是功课，但是您可以做一个变量，然后检查输入的数字是否大于或小于保存的变量.

>

if(input > max)
  max = input;

还有

if(input < min)
  min = input;

I don't have any idea how to display the largest and smallest number after the user enter -1.

Note: I also have to display the sum of all of this number and the average of this sum.

Here's my code so far:

public static void main(String[] args) {
    // store
    int cnt = 0;
    int acumulator = 0;
    int larger = 0;
    int smaller = 0;
    int number;
    // inputs
    System.out.println("enter the number all the number");
    Scanner kb = new Scanner(System.in);
    number = kb.nextInt();
    // loop
    while (number != -1) {
        acumulator += number;
        number = kb.nextInt();
        cnt++;//
    }
    double average = (acumulator / cnt);
    System.out.println(" The total of your number is=" + acumulator);
    System.out.println(" The average of your number is=" + average);
}

解决方案

Seems like schoolwork, but what you could do is making a var and checking in your while if the input number is higher or lower then the saved var.

if(input > max)
  max = input;

And

if(input < min)
  min = input;

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