Python上的数字三角形 [英] Triangle of numbers on Python

问题描述

我被要求写一个循环系统，打印以下内容:

I'm asked to write a loop system that prints the following:

0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8
0 1 2 3 4 5 6 7
0 1 2 3 4 5 6
0 1 2 3 4 5
0 1 2 3 4
0 1 2 3
0 1 2
0 1
0

但是，我的脚本会显示以下内容:

However, my script prints this:

0 1 2 3 4 5 6 7 8 9 
0 1 2 3 4 5 6 7 8 

0 1 2 3 4 5 6 7 


0 1 2 3 4 5 6 
# ... and so on

要修改的代码为:

for row in range(10):
    for column in range(row):
        print ''
    for column in range(10-row):
        print column,

推荐答案

循环太多，只需要两个循环即可:

You have too many loops, you only need two:

for row in range(10):
    for column in range(10-row):
        print column,
    print("")

0 1 2 3 4 5 6 7 8 9 
0 1 2 3 4 5 6 7 8 
0 1 2 3 4 5 6 7 
0 1 2 3 4 5 6 
0 1 2 3 4 5 
0 1 2 3 4 
0 1 2 3 
0 1 2 
0 1 
0 

或从将来导入的打印内容适用于python2.7和3:

Or importing print from future which will work for python2.7 and 3:

from __future__  import print_function

for row in range(10):
    for column in range(10-row):
        print(column,end=" ")
    print()

如果您想要一个班轮，可以使用join:

If you want a one liner you can use join:

print("\n".join([" ".join(map(str,range(10-row))) for row in range(10)]))

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