如何在Lua中找到由关键字内的字母组成的单词? [英] How can I find the words consist of the letters inside the keyword in Lua?

问题描述

例如，我有一个关键字"abandoned"，我想从存储这些单词的数组中找到包含该关键字字母的单词，例如"done"，"abandon"，band".搜索吗?

For example, I have a keyword "abandoned" and I want to find the words that contains letters of this keyword such as "done", "abandon", band", from the arrays I stored those words. How can I search it?

我尝试编写此代码，但无法正常工作.我写了一个包含关键字和单词的函数.然后我将关键字字母放到keywordletters数组中，然后将单词字母放到wordletters数组中.

I tried to write this code but not working properly. I wrote a function which takes the keyword and the word. Then i put letters of keyword to keywordletters array and the letters of the word into wordletters array.

然后我写了一个匹配字母的循环.如果wordletters数组与keywordletters数组的字母匹配，则我将当前wordletters元素分配为nil，然后将keywordletters元素设置为nil.因为我们不能第二次使用它.

Then i wrote a loop for matching letters. If the wordletters array match with the letter of keywordletters array, then i assigned the current wordletters element nil and then i made the keywordletters element nil. Because we can't use it second time.

在所有循环之后，我检查了wordletters数组.如果它有一个不是nil的元素，那么我返回false.但是，我不想要它.你能帮我吗?

After all loops, i checked the wordletters array. If it has an element which is not nil then i returned false. However, it's not working how i want. Can you help me out?

ı我解决了我的问题，并相应地编辑了代码.

ıI solved my problem and edited the code accordingly.

这是我的代码:

  function consistLetters(keyword,word)

keywordletters={ }
    wordletters= { }
local found=false
findLetters(keyword,keywordletters)
findLetters(word,wordletters)


for i=1, #wordletters,1 do
    for j=1, #keywordletters,1 do
        if(keywordletters[j]~="") then
            if(wordletters[i]==keywordletters[j]) then
                keywordletters[j]="" 
                found=true;
                break
            end
         end
    end
    if found~=true then
        return false
    end
   found=false; 
end     

  end

推荐答案

例如，我有一个关键字"abandoned"，我想从存储这些单词的数组中找到包含该关键字字母的单词，例如"done"，"abandon"，band".搜索吗?

For example, I have a keyword "abandoned" and I want to find the words that contains letters of this keyword such as "done", "abandon", band", from the arrays I stored those words. How can I search it?

您可以简单地使用关键字作为正则表达式(在Lua中也称为模式")，将其字母作为一组，例如('^[%s]+$'):format('abandoned'):match('done').

You can simply use the keyword as a regular expression (aka "pattern" in Lua), using it's letters as a set, for instance ('^[%s]+$'):format('abandoned'):match('done').

local words = {'done','abandon','band','bane','dane','danger','rand','bade','rand'}
local keyword = 'abandoned'

-- convert keyword to a pattern and match it against each word
local pattern = string.format('^[%s]+$', keyword)
for i,word in ipairs(words) do
    local matches = word:match(pattern)
    print(word, matches and 'matches' or 'does not match')
end

输出:

done    matches
abandon matches
band    matches
bane    matches
dane    matches
danger  does not match
rand    does not match
bade    matches
rand    does not match

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