克隆lua状态 [英] Clone a lua state

问题描述

最近，在使用C ++和Lua进行开发时遇到了很多困难.我的情况是:由于某种原因，我的C ++程序中可能有成千上万的Lua状态.但是这些状态在初始化后应该是相同的.当然，我可以为每个状态执行luaL_loadlibs()和lua_loadfile()，但这非常繁重(实际上，即使是一个初始状态，对我来说也要花费相当长的时间).因此，我想知道以下模式:保持一个单独的Lua状态(必须初始化的唯一状态)，然后将其克隆为其他Lua状态，那有可能吗?

Recently, I have encountered many difficulties when I was developing using C++ and Lua. My situation is: for some reason, there can be thousands of Lua-states in my C++ program. But these states should be same just after initialization. Of course, I can do luaL_loadlibs() and lua_loadfile() for each state, but that is pretty heavy(in fact, it takes a rather long time for me even just initial one state). So, I am wondering the following schema: What about keeping a separate Lua-state(the only state that has to be initialized) which is then cloned for other Lua-states, is that possible?

推荐答案

当我像你一样开始使用Lua时，我曾经写过一个包含数千个州的程序，遇到了同样的问题和想法，直到意识到自己完全做到了错误:)

When I started with Lua, like you I once wrote a program with thousands of states, had the same problem and thoughts, until I realized I was doing it totally wrong :)

Lua具有协程和线程，您需要使用这些功能来完成所需的工作.一开始它们可能会有些棘手，但是几天后您就应该能够理解它们，这很值得您花时间.

Lua has coroutines and threads, you need to use these features to do what you need. They can be a bit tricky at first but you should be able to understand them in a few days, it'll be well worth your time.

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