从表中获取一个值并将其分配给另一个值，无需重复 [英] Getting one value from a table and assigning it to another with no repeats

问题描述

具体来说，这是针对Garry's Mod的，但是我认为在这个问题上没有太大的意义.我想要做的是得到一个玩家，并将他们的值设置为另一位随机玩家(因此，每个玩家都有一个随机的目标").我想做到这一点而无需重复，这样就不会将玩家分配给自己.为了更好地说明:

与这张图片的唯一区别是，我希望将每个玩家分配给另一个随机玩家，所以更像是玩家1 =>玩家5，玩家3 =>玩家2，等等.

此刻是我的代码，但这总是使一个人未被选中:

validTargets = {}
TargetList = {}

local Swap = function(array, index1, index2)
    array[index1], array[index2] = array[index2], array[index1]
end

GetShuffle = function(numelems)
    local shuffle = {}
    for i = 1, numelems do
        shuffle[#shuffle + 1] = i
    end
    for ii = 1, numelems do
        Swap(shuffle, ii, math.random(ii, numelems))        
    end
    return shuffle
end

function assignTargets()
    local shuffle = GetShuffle(#playing)
    for k,v in ipairs(shuffle) do
        TargetList[k] = v
    end

    SyncTargets()
end

function SyncTargets()
    for k,v in pairs(TargetList) do
        net.Start("sendTarget")
            net.WriteEntity(v)
        net.Send(k)
    end
end

解决方案

我有一个lua函数，在给定n的情况下，该函数会生成从1到n的数字随机洗牌. 该方法基于热门算法生成的随机排列元素数组.

您可以尝试像这样使用

:

local Swap = function(array, index1, index2)
    array[index1], array[index2] = array[index2], array[index1]
end


GetShuffle = function(numelems)
    local shuffle = {}
    for i = 1, numelems do
        shuffle[#shuffle + 1] = i
    end
    for ii = 1, numelems do
        Swap(shuffle, ii, math.random(ii, numelems))        
    end
    return shuffle
end

function assignTargets()
    local shuffle = GetShuffle(#playing) --assuming `playing` is a known global
    for k,v in ipairs(shuffle) do
        TargetList[k] = v
    end
end

Specifically, this is for Garry's Mod, however I don't think that matters too much in this problem. What I want to do is get one player, and set their value to another random player (so every player has a random 'target'). I want to do this with no repeats, and so that a player is not assigned to their self. To better illustrate:

The only difference to that picture is that I want each player to be assigned to another random player, so more like player1 => player 5, player 3 => player 2, etc.

Here is my code at the moment, however this always leaves one person unpicked:

validTargets = {}
TargetList = {}

local Swap = function(array, index1, index2)
    array[index1], array[index2] = array[index2], array[index1]
end

GetShuffle = function(numelems)
    local shuffle = {}
    for i = 1, numelems do
        shuffle[#shuffle + 1] = i
    end
    for ii = 1, numelems do
        Swap(shuffle, ii, math.random(ii, numelems))        
    end
    return shuffle
end

function assignTargets()
    local shuffle = GetShuffle(#playing)
    for k,v in ipairs(shuffle) do
        TargetList[k] = v
    end

    SyncTargets()
end

function SyncTargets()
    for k,v in pairs(TargetList) do
        net.Start("sendTarget")
            net.WriteEntity(v)
        net.Send(k)
    end
end

解决方案

I have a lua function that generates a Random shuffle of numbers from 1 to n, given n. The method is based on a popular algorithm to generate a random permutation of an array of elements .

You can try using that like so:

local Swap = function(array, index1, index2)
    array[index1], array[index2] = array[index2], array[index1]
end


GetShuffle = function(numelems)
    local shuffle = {}
    for i = 1, numelems do
        shuffle[#shuffle + 1] = i
    end
    for ii = 1, numelems do
        Swap(shuffle, ii, math.random(ii, numelems))        
    end
    return shuffle
end

function assignTargets()
    local shuffle = GetShuffle(#playing) --assuming `playing` is a known global
    for k,v in ipairs(shuffle) do
        TargetList[k] = v
    end
end

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