R日期与lubridate [英] R sequence of dates with lubridate

问题描述

我正在尝试获取lubridate的日期序列

Hi I'm trying to get a sequence of dates with lubridate

这不起作用

seq(ymd('2012-04-07'),ymd('2013-03-22'),by=week(1))

基本命令

seq(as.Date('2012-04-7'),as.Date('2013-03-22'),'weeks')

可以，但是我想知道是否有一种使用lubridate的优雅方法.

does, but I'd like to know if there is an elegant way to do this with lubridate.

编辑

请忽略:解决了我自己，只留给后代.很高兴在必要时将其删除.

Please ignore : solved myself so leaving up for posterity only. Happy to have this deleted if necessary.

seq(ymd('2012-04-07'),ymd('2013-03-22'),by='weeks')

有花招

推荐答案

ymd是用于解析日期字符串并返回POSIXct对象的包装器.

ymd is a wrapper to parse date strings and returns a POSIXct object.

您只需要使用?seq.POSIXt(不是lubridate)中描述的标准术语来定义星期

You simply need to use standard terminology described in ?seq.POSIXt (not lubridate) to define weeks

seq(ymd('2012-04-07'),ymd('2013-03-22'), by = '1 week')
seq(ymd('2012-04-07'),ymd('2013-03-22'), by = 'weeks')

将起作用

将

seq(ymd('2012-04-07'),ymd('2013-03-22'), by = '2 week')

您可以将lubridate Period类对象强制为difftime，但这似乎是不必要的

You could coerce the lubridate Period class object to a difftime, but that seems rather unnecessary

seq(ymd('2012-04-07'),ymd('2013-03-22'), by = as.difftime(weeks(1)))

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