是否可以在Python中针对XSD 1.1验证XML文件? [英] Is it possible to validate an XML file against XSD 1.1 in Python?

问题描述

我想使用lxml.XMLSchema针对XSD文件验证XML文件.但是问题是XSD在1.1中.所以它行不通.

I want validate an XML file against an XSD file using lxml.XMLSchema. But the problem is the XSD is in 1.1. So it doesn't work.

这是XML的一部分:

<?xml version="1.0" encoding="UTF-8"?>
<dictionary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:noNamespaceSchemaLocation="!!assert.xsd">
  <SizeType>10</SizeType>
</dictionary>

这是它的XSD文件:

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           elementFormDefault="qualified">
  <xs:element name="SizeType">
    <xs:simpleType>
      <xs:restriction base="xs:integer">
        <xs:assertion test="$value = 10"/>
      </xs:restriction>
    </xs:simpleType>
  </xs:element>
</xs:schema>

那么，是否有可能针对使用xs:assertion语句(1.1)的XSD文件验证XML文件?

So, is it possible to validate an XML file against a XSD file that uses xs:assertion statements (1.1)?

我认为这个问题与此密切相关:具有架构1.1的lxml

I think this question is closely related to this: lxml with schema 1.1

推荐答案

截至2013年11月上旬，仅以下XML处理器支持XSD 1.1:

As of early November 2013, only the following XML processors support XSD 1.1:

• 带有PsychoPath XPath 2.0的Xerces-J
• Saxon EE
• 阿尔托瓦

• Xerces-J with PsychoPath XPath 2.0
• Saxon EE
• Altova

还没有用Python编写的XML解析器可以针对XSD 1.1进行验证.

There is no XML parser written in Python that validates against XSD 1.1 yet.

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