Python LXML解析SVG文件 [英] Python lxml parsing svg file

问题描述

我正在尝试从 http://kanjivg.tagaini.net/解析.svg文件，但我无法成功提取其中的信息.

I'm trying to parse .svg files from http://kanjivg.tagaini.net/ , but I can't successfully extract the information inside.

(完整文件) http://www.filedropper.com /0f9ab

0f9ab.svg的一部分看起来像这样:

A part of 0f9ab.svg looks like this:

<svg xmlns="http://www.w3.org/2000/svg" width="109" height="109" viewBox="0 0 109 109">
<g id="kvg:StrokePaths_0f9ab" style="fill:none;stroke:#000000;stroke-width:3;stroke-linecap:round;stroke-linejoin:round;">
<g id="kvg:0f9ab" kvg:element="嶺">
    <g id="kvg:0f9ab-g1" kvg:element="山" kvg:position="top" kvg:radical="general">
        <path id="kvg:0f9ab-s1" kvg:type="㇑a" d="M53.26,9.38c0.99,0.99,1.12,2.09,1.12,3.12c0,0.67,0.06,8.38,0.06,13.01"/>
        <path id="kvg:0f9ab-s2" kvg:type="㇄a"
    </g>
</g>
</g>

我的.py文件:

import lxml.etree as ET

svg = ET.parse('0f9ab.svg')
print(svg)  # <lxml.etree._ElementTree object at 0x7f3a2f659ec8>

# AttributeError: 'lxml.etree._ElementTree' object has no attribute 'tag'
print(svg.tag)

# TypeError: 'lxml.etree._ElementTree' object is not subscriptable
print(svg[0])

# TypeError: 'lxml.etree._ElementTree' object is not iterable
for child in svg:
    print(child)

# None
print(svg.find("./svg"))

# []
print(svg.findall("//g"))

# []
print(svg.xpath("//g"))

目的

我尝试了所有我可以想到的操作，但是没有任何东西可以使我从.svg文件中获取任何数据. 我想提取kvg:element="kanji"中的汉字(日语字符)(在不同的深度级别).

Purpose

I tried all kinds of operations I could think of, but nothing gets me any data from the .svg file. I want to extract the kanji (Japanese character) in kvg:element="kanji" (which are at different depth levels).

1. 为此使用了错误的软件包吗?
2. 如果没有，如何从已解析的.svg文件中提取信息?

其他解决方案

• 我当然可以将文件读取为字符串并进行搜索 对于kvg:element="，但我想以适当的方式提取xml /svg.
• 我以前使用过xmltodict，但是提取kvg:element时我的代码变得非常混乱，因为它们的深度级别不同.

Other solution

• I could of course I could just read the file as a string and search for kvg:element=", but I would like to proper way of extracting xml / svg.
• I used xmltodict before, but my code became really messy extracting kvg:element, because they were at different depth levels.

推荐答案

.parse()返回 ElementTree ，代表整个树.要查询单个节点，您需要一个元素，最有可能是树.

.parse() returns an ElementTree, which represents the tree as a whole. To query individual nodes, you need an Element, most likely the root element of the tree.

使用以下代码替换部分代码:

Replace part of your code with this:

xml = ET.parse('0f9ab.svg')
svg = xml.getroot()
print(svg)  # <lxml.etree._ElementTree object at 0x7f3a2f659ec8>

我想您会成功的.

还请注意，.findall()需要相对路径，并且在您的情况下还需要名称空间限定符:

Note also that .findall() requires a relative path and, in your case, a namespace qualifier:

print(svg.findall(".//{http://www.w3.org/2000/svg}g"))

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