如何跳过lxml中的URI验证? [英] How do I skip validating the URI in lxml?

问题描述

我正在使用lxml解析一些xml文件.我没有创建它们，我只是在解析它们.一些文件包含用于命名空间的无效uri.例如:

I am using lxml to parse some xml files. I don't create them, I'm just parsing them. Some of the files contain invalid uri's for the namespaces. For instance:

'D:\Path\To\some\local\file.xsl'

当我尝试处理它时出现错误:

I get an error when I try to process it:

lxml.etree.XMLSyntaxError: xmlns:xsi: 'D:\Path\To\some\local\file.xsl' is not a valid URI

是否有一种简便的方法可以将某些无效的uri替换为某些内容(例如" http://www. googlefsdfsd.com/')?我想写一个正则表达式，但是希望有一种更简单的方法.

Is there an easy way to replace any invalid uri's with something (anything, such as 'http://www.googlefsdfsd.com/')? I thought of writing a regex but was hoping for an easier way.

推荐答案

解析器不喜欢的是名称空间uri中的反斜杠.

What the parser doesn't like are the backslashes in the namespace uri.

要在无效的uri情况下解析xml，可以实例化 lxml.etree recover参数设置为True的.XMLParser ，然后使用它来解析文件:

To parse the xml despite the invalid uris, you can instantiate an lxml.etree.XMLParser with the recover argument set to True and then use that to parse the file:

from lxml import etree
recovering_parser = etree.XMLParser(recover=True)
xml = etree.parse("xmlfile.xml", parser=recovering_parser)
...

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