没有嵌套节点.如何获取一条信息然后分别获取其他信息? [英] No nested nodes. How to get one piece of information and then to get additional info respectively?
问题描述
对于下面的代码,我需要分别获取日期和时间+ hrefs + formats + ...(未显示).
For the code below I need to get dates and their times+hrefs+formats+...(not shown) respectively.
<div class="showtimes">
<h2>The Little Prince</h2>
<div class="poster" data-poster-url="http://www.test.com">
<img src="http://www.test.com">
</div>
<div class="showstimes">
<div class="date">9 December, Wednesday</div>
<span class="show-time techno-3d">
<a href="http://www.test.com" class="link">12:30</a>
<span class="show-format">3D</span>
</span>
<span class="show-time techno-3d">
<a href="http://www.test.com" class="link">15:30</a>
<span class="show-format">3D</span>
</span>
<span class="show-time techno-3d">
<a href="http://www.test.com" class="link">18:30</a>
<span class="show-format">3D</span>
</span>
<div class="date">10 December, Thursday</div>
<span class="show-time techno-2d">
<a href="http://www.test.com" class="link">12:30</a>
<span class="show-format">2D</span>
</span>
<span class="show-time techno-3d">
<a href="http://www.test.com" class="link">15:30</a>
<span class="show-format">3D</span>
</span>
</div>
</div>
为此,我使用以下代码(python).
To do this, I use this code (python).
for dates in movie.xpath('.//div[@class="showstimes"]/div[@class="date"]'):
date = dates.xpath('.//text()')[0]
# for times in dates.xpath('//following-sibling::span[1 = count(preceding-sibling::div[1] | (.//div[@class="date"])[1])]'):
# for times in dates.xpath('//following-sibling::span[contains(@class,"show-time")]'):
# for times in dates.xpath('.//../span[contains(@class,"show-time")]'):
# for times in dates.xpath('//following-sibling::span[preceding-sibling::div[1][.="date"]]'):
time = times.xpath('.//a/text()')[0]
url = times.xpath('.//a/@href')[0]
format_type = times.xpath('.//span[@class="show-format"]/text()')[0]
获取日期不是问题,但是我有一个问题,如何分别获取特定日期的其余信息.尝试了许多不同的方式-运气不佳(在其中一些评论中).当我需要的节点一个接一个(在同一级别上)时,我找不到解决该情况的方法.在这种情况下:
To get dates is not a problem, but I have a problem how to get the rest info for particular date respectively. Tried many different ways - no luck (in comments some of them). I can't find the way how to deal with the case when the nodes that I need are one under another (on the same level?). In this case:
-> div Date1
-> span Time1
-> span href1
-> span Format1
-> span Time2
-> span href2
-> span Format2
-> span Time3
-> span href3
-> span Format3
-> div Date2
-> span Time1
-> span href1
-> span Format1
# etc etc
推荐答案
事实证明,lxml
支持从XPath表达式中引用python变量,这被证明对这种情况很有用,例如,对于每个div date
,您都可以获取后继同级span
,其中最近的同级同级div date
是当前div date
,其中对当前div date
的引用存储在python变量中 dates
:
Turns out that lxml
support referencing python variable from XPath expression, which proven to be useful for this case i.e for every div date
, you can get the following sibling span
which the nearest preceding sibling div date
is the current div date
, where reference to the current div date
is stored in python variable dates
:
for dates in movie.xpath('.//div[@class="showstimes"]/div[@class="date"]'):
date = dates.xpath('normalize-space()')
for times in dates.xpath('following-sibling::span[preceding-sibling::div[1]=$current]', current=dates):
time = times.xpath('a/text()')[0]
url = times.xpath('a/@href')[0]
format_type = times.xpath('span/text()')[0]
print date, time, url, format_type
输出:
'9 December, Wednesday', '12:30', 'http://www.test.com', '3D'
'9 December, Wednesday', '15:30', 'http://www.test.com', '3D'
'9 December, Wednesday', '18:30', 'http://www.test.com', '3D'
'10 December, Thursday', '12:30', 'http://www.test.com', '2D'
'10 December, Thursday', '15:30', 'http://www.test.com', '3D'
参考文献:
- https://stackoverflow.com/a/17750629/2998271
- http://lxml.de/xpathxslt.html#the-xpath-method
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