如何强制make始终重建文件 [英] How to force make to always rebuild a file

问题描述

我的项目中有一个version.c文件，其中包含项目的当前版本以及从makefile作为定义(-D编译器选项)传递的其他内容.

I have a version.c file in my project that contains current revision of the project and some other stuff that is passed as a definition (-D compiler option) from makefile.

我知道无论修改日期如何，总是强制使make编译version.c.

I know that to force make to compile version.c always regardless of modification date I can touch version.c.

是否只有makefile实现此目的?如果我写.PHONY : version.o，则目标文件根本无法构建.

Is there a makefile only way to achieve this? If I write .PHONY : version.o the object file doesn't get build at all.

这是我的makefile:

Here is my makefile:

export CC = gcc


export MODULES = $(sort \
     sys \
     cim \
     version \
)

export FILES = $(sort \
             main.c \
             cim.c \
             version.c \
)

VPATH = $(MODULES)

OBJS = $(FILES:.c=.o)

INCLUDES = $(addprefix -I,$(MODULES))

all:$(OBJS)
    $(CC) $(INCLUDES) $(OBJS) -o main.exe


clean:
    rm -rf *.o *.exe

cim.o: cim.c
main.o: main.c cim.o
version.o: version.c

.PHONY: version.o

.c.o :
    $(CC) $(CFLAGS) $(INCLUDES) -c $<

推荐答案

经典方法是:

version.o:   .FORCE

.FORCE:

(您可能会添加.PHONY: .FORCE).假定文件'.FORCE'不存在，所以它始终是'created'，所以version.o总是过时，因此version.o总是被编译.

(and you might add .PHONY: .FORCE). The file '.FORCE' is presumed not to exist, so it is always 'created', so version.o is always out of date w.r.t it, so version.o is always compiled.

我不确定将version.o制成伪造文件是否正确；它实际上是一个真实的文件，而不是假的文件.

I'm not sure that making version.o into a phony file is correct; it is actually a real file, not a phony one.

这篇关于如何强制make始终重建文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！