模式匹配具有多个可执行目标的Makefile [英] Pattern matching Makefile with multiple executable targets

问题描述

我有一个生成文件，该文件可构建多个可执行目标prog0 ... prog99.每个可执行文件的所有编译器和链接选项均相同:

I have a makefile that builds multiple executable targets prog0...prog99. All the compiler and link options are the same for each executable:

prog0: prog0.cpp prog0.h
   $(CC) $(CFLAGS) prog0 prog0.cpp $(LINKFLAGS)

prog1: prog1.cpp prog1.h
   $(CC) $(CFLAGS) prog1 prog1.cpp $(LINKFLAGS)
.
.
.
.
prog99: prog99.cpp prog99.h
   $(CC) $(CFLAGS) prog99 prog99.cpp $(LINKFLAGS)

我想知道是否有一种类似于构建目标文件的模式匹配技术可以应用到上面，以减少makefile的重复.

I was wondering if there is a pattern matching technique similar to building object files that could be applied to the above, so as to reduce the repetition of the makefile.

推荐答案

是的，当然:

prog%: prog%.cpp prog%.h
    $(CC) $(CFLAGS) $@ $< $(LINKFLAGS)

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