处理从单个输入生成的多个文件 [英] Processing multiple files generated from single input

问题描述

我有一个数据文件，该文件由脚本处理以产生多个输出文件.这些输出文件中的每一个都将被进一步处理.创建哪些文件取决于输入文件的内容，因此我无法明确列出它们.我不太清楚如何引用Makefile中生成的各种文件.

I have a data file that is processed by a script to produce multiple output files. Each of these output files is then processed further. Which files are created depends on the contents of the input file, so I can't list them explicitly. I can't quite figure out how to refer to the various files that are generated in a makefile.

目前，我有这样的事情:

Currently, I have something like this:

final.out: *.out2
  merge_files final.out $(sort $^)

%.out2: %.out1
  convert_files $?

%.out1: data.in
  extract_data data.in

此操作失败，并显示No rule to make target '*.out2', needed by 'final.out'.我认为这是因为.out2文件尚不存在，因此通配符表达式未按我希望的方式替换.我尝试使用通配符函数，但是失败，因为先决条件列表最终为空.

This fails with No rule to make target '*.out2', needed by 'final.out'. I assume this is because the .out2 files don't exist yet and therefore the wildcard expression isn't replaced the way I would like it to. I have tried to use the wildcard function but that fails because the list of prerequisites ends up being empty.

任何指针将不胜感激.

推荐答案

编辑:修复了第二遍中的先决条件列表.

EDIT: fixed the list of prerequisites in second pass.

您显然无法在运行extract_data命令之前计算中间文件的列表.在这种情况下，一种解决方案是运行make两次.第一次生成*.out1文件，第二次完成作业.您可以使用一个空的虚拟文件来标记是否 extract_data命令应再次运行还是不运行:

You apparently cannot compute the list of intermediate files before running the extract_data command. In this case a solution consists in running make twice. One first time to generate the *.out1 files and a second time to finish the job. You can use an empty dummy file to mark whether the extract_data command shall be run again or not:

ifeq ($(FIRST_PASS_DONE),)
final.out: .dummy
    $(MAKE) FIRST_PASS_DONE=yes

.dummy: data.in
    extract_data $<
else
OUT1 := $(wildcard *.out1)
OUT2 := $(patsubst %.out1,%.out2,$(OUT1))

final.out: $(OUT2)
    merge_files $@ $(sort $^)

%.out2: %.out1
    convert_files $?
endif

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