如何编写一个makefile以在不同目录中生成目标文件和可执行文件? [英] How to write a makefile to generate object files and executable in different directory?

问题描述

现在要继续进行，我需要更改现有Makefile的显示方式.

Now to proceed further I need to change the presentation of existing Makefile.

目前我正在使用:

~/Linuz/src: 1.c, 2.c, 3.c ...

~/Linuz/inc: abc.h, xyz.h

和makefile位于:~/Linuz/some_other_dir/

and makefile is in: ~/Linuz/some_other_dir/

但是需要更改结构.

1. 想从(~/Linuz/src/和~/linuz/inc)创建一个库
2. 库将用于获取可执行文件.应用程序源文件(.c文件)位于~/Linuz/app/
中
3. ~/Linuz/bin/应该在编译期间创建，以存储所有目标文件和可执行文件.

1. Want to create a library from (~/Linuz/src/ and ~/linuz/inc)
2. Library will be used to get executable. Application source files(.c files) are in ~/Linuz/app/
3. ~/Linuz/bin/ should be created during compilation to store all the object files and executable file.

任何建议??

我的makefile如下:

all: Library.a

%.o: ../src/%.c

    $(CC) $(CFLAGS) -I../inc/ -c -o $@ $^

Library.a:  $(SRC_DIR)/1.c $(SRC_DIR)/2.c $(SRC_DIR)/3.c $(SRC_DIR)/4.c $(SRC_DIR)/5.c

    $(CC) $(LDFLAGS) -o $@ $^

all: prog

%.o: ./*.c

    $(CC) $(CFLAGS) -ILibrary.a -c -o $@ $^


prog:   $(APP_DIR)/app1.c $(APP_DIR)/app2.c $(APP_DIR)/app3.c

clean:
    rm -f *.o my_program

推荐答案

假设您的代码体系结构如下:

Let assume that your code architecture looks like that:

└── linuz
    ├── app
    │   ├── app1.c
    │   ├── app2.c
    │   └── app3.c
    ├── bin
    ├── inc
    │   └── any.h
    ├── some_other_dir
    │   └── Makefile
    └── src
        ├── 1.c
        ├── 2.c
        └── 3.c

因此您的Makefile可能是:

So your Makefile could be:

all: ../bin/libmy_lib.a ../bin/my_program


../bin/my_lib_%.o: ../src/%.c
    $(CC) $(CFLAGS) -I../inc -c -o $@ $^

../bin/libmy_lib.a: ../bin/my_lib_1.o ../bin/my_lib_2.o  ../bin/my_lib_3.o
    ar rcs $@ $^

../bin/my_app_%.o: ../app/%.c
    $(CC) $(CFLAGS) -I../inc -c -o $@ $^

../bin/my_program: ../bin/my_app_app1.o ../bin/my_app_app2.o  ../bin/my_app_app3.o ../bin/libmy_lib.a
    $(CC) $(LDFLAGS) -L../bin/ -lmy_lib -o $@ $^


clean:
    rm -f ../bin/*.o ../bin/libmy_lib.a ../bin/my_program

有关说明，请参阅您的

For the explanation, refer to your previous question

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