无法从“无效*"转换为“节点*" [英] Cannot convert from 'void *' to 'node *'

问题描述

我的代码从'void *'转换为'NODE *'时遇到问题

I am having a problem with my code to convert from 'void *' to 'NODE *'

有人可以帮助我解决这个问题吗?

Can anyone help me get around this problem?

NODE *list_create(void *data)
{
NODE *node;
if(!(node = malloc(sizeof(NODE)))) return NULL;
node->data=data;
node->next=NULL;
return node;
}

我在=号正下方发现错误. 任何帮助将不胜感激！

I get the error right underneath the = sign. Any help would be greatly appreciated!

推荐答案

您尚未指定错误，但是从代码的外观来看，最有可能是类型转换错误，例如:

You have not specified the error, but assuming from the looks of the code, most probable is the type conversion error, something like:

无法将void *转换为NODE *

Cannot convert void* to NODE*

该问题被标记为C，并且此处编写的代码也有效C，但无效C++.因此，如果出现错误，可以安全地假定正在使用C ++编译器来编译代码.

The question is tagged with C and the code written here is also valid C, but invalid C++. So if there is an error, it can be safely assumed that a C++ compiler is being used to compile the code.

要消除该错误，请使用C编译器.或者如果您想使用C ++编译器，则显式键入cast malloc的返回值.

To remove the error, either use a C compiler; or if you want to stick with a C++ compiler, explicitly type cast the return value of malloc.

if(!(node = (NODE*)malloc(sizeof(NODE)))) return NULL;

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