来自关键路径的嵌套字典值 [英] Nested dictionary value from key path

问题描述

借助键路径从嵌套字典中获取值，这是dict:

Get the value from a nested dictionary with the help of key path, here is the dict:

json = {
    "app": {
        "Garden": {
            "Flowers": {
                "Red flower": "Rose",
                "White Flower": "Jasmine",
                "Yellow Flower": "Marigold"
            }
        },
        "Fruits": {
            "Yellow fruit": "Mango",
            "Green fruit": "Guava",
            "White Flower": "groovy"
        },
        "Trees": {
            "label": {
                "Yellow fruit": "Pumpkin",
                "White Flower": "Bogan"
            }
        }
    }

该方法的输入参数是点分隔的关键路径，从关键路径="app.Garden.Flowers.white Flower"需要打印'Jasmine'.到目前为止，我的代码:

The input parameter to the method is the key path with dots separated, from the key path = "app.Garden.Flowers.white Flower" need to print 'Jasmine'. My code so far:

import json
with open('data.json') as data_file:    
  j = json.load(data_file)


def find(element, JSON):     
  paths = element.split(".")  
  # print JSON[paths[0]][paths[1]][paths[2]][paths[3]]
  for i in range(0,len(paths)):
    data = JSON[paths[i]]
    # data = data[paths[i+1]]
    print data



find('app.Garden.Flowers.White Flower',j)

推荐答案

非常接近.您需要(就像您在评论中一样)以递归方式遍历主JSON对象.您可以通过存储最外面的键/值的结果，然后使用它来获取下一个键/值等，直到您脱离路径为止.

Very close. You need to (as you had in your comment) recursively go through the main JSON object. You can accomplish that by storing the result of the outermost key/value, then using that to get the next key/value, etc. till you're out of paths.

def find(element, JSON):     
  paths = element.split(".")
  data = JSON
  for i in range(0,len(paths)):
    data = data[paths[i]]
  print data

尽管如此，您仍然需要提防KeyErrors.

You still need to watch out for KeyErrors though.

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