用另一本字典对字典排序 [英] sort dictionary by another dictionary

问题描述

我在用字典制作排序列表时遇到了问题. 我有这个清单

I've been having a problem with making sorted lists from dictionaries. I have this list

list = [
    d = {'file_name':'thisfile.flt', 'item_name':'box', 'item_height':'8.7', 'item_width':'10.5', 'item_depth':'2.2', 'texture_file': 'red.jpg'},
    d = {'file_name':'thatfile.flt', 'item_name':'teapot', 'item_height':'6.0', 'item_width':'12.4', 'item_depth':'3.0' 'texture_file': 'blue.jpg'},
    etc.
]

我试图遍历列表，然后

• 从每个字典中创建一个新列表，其中包含该字典中的项目. (随着用户做出选择，它会改变哪些项目以及需要添加到列表中的项目)
• 对列表进行排序

我说排序的时候，我想像这样创建一个新字典

When I say sort, I imagine creating a new dictionary like this

order = {
    'file_name':    0,
    'item_name':    1, 
    'item_height':  2,
    'item_width':   3,
    'item_depth':   4,
    'texture_file': 5
}

，并按顺序字典中的值对每个列表进行排序.

and it sorts each list by the values in the order dictionary.

在执行脚本的过程中，所有列表看起来都像这样

During one execution of the script all the lists might look like this

['thisfile.flt', 'box', '8.7', '10.5', '2.2']
['thatfile.flt', 'teapot', '6.0', '12.4', '3.0']

另一方面，它们可能看起来像这样

on the other hand they might look like this

['thisfile.flt', 'box', '8.7', '10.5', 'red.jpg']
['thatfile.flt', 'teapot', '6.0', '12.4', 'blue.jpg']

我想我的问题是，我将如何根据字典中的特定值创建一个列表，然后将其与另一个具有与第一个字典相同键的字典中的值进行排序?

I guess my question is how would I go about making a list from specific values from a dictionary and sorting it by the values in another dictionary which has the same keys as the first dictionary?

感谢任何想法/建议，对不起的行为表示抱歉-我仍在学习python/编程

Appreciate any ideas/suggestions, sorry for noobish behaviour - I am still learning python/programming

推荐答案

第一个代码框的Python语法无效(我怀疑d =部分是多余的...?)，并且不明智地践踏了内置代码名称list.

The first code box has invalid Python syntax (I suspect the d = parts are extraneous...?) as well as unwisely trampling on the built-in name list.

反正，例如:

d = {'file_name':'thisfile.flt', 'item_name':'box', 'item_height':'8.7', 
     'item_width':'10.5', 'item_depth':'2.2', 'texture_file': 'red.jpg'}

order = {
    'file_name':    0,
    'item_name':    1, 
    'item_height':  2,
    'item_width':   3,
    'item_depth':   4,
    'texture_file': 5
}

获得所需结果['thisfile.flt', 'box', '8.7', '10.5', '2.2', "red.jpg']的一种巧妙方法是:

one nifty way to get the desired result ['thisfile.flt', 'box', '8.7', '10.5', '2.2', "red.jpg'] would be:

def doit(d, order):
  return  [d[k] for k in sorted(order, key=order.get)]

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