如何在Scala中使用动态[递增]名称创建变量 [英] How to create variables with dynamic [incremental] names in Scala

问题描述

我想创建一组具有动态名称的变量，并在for循环中分配它们，例如:

I want to create a set of variables with dynamic names and assigning each of them in for loop, for example:

val V1,V2,V3,V4

for (i<- 1 until 5){
   V<i>=doc1.map(array of string)
}

如何创建这些变量?

推荐答案

与其他任何编程语言一样，您在Scala中使用数组.语法与Java稍有不同

You use an array in Scala just like in any other programming language. The syntax varies slightly from Java

val v = new Array[String](5)
for (i <- 1 until 5)
  v(i) = doc1.map(array of string)

注意:变量需要以小写字母开头. Scala中的数组索引从零开始，因此您必须注意为数组分配的项目数(5)与数组的最后一个索引(4).与Java不同，您的数组索引v(i)用圆括号而不是方括号括起来.

Notes: The variable needs to start with a lower case letter. Array indexes in Scala start at zero, so you have to be careful about the number of items you allocate for your array (5) versus the last index of the array (4). Unlike Java, your array index v(i) is enclosed in round braces instead of square braces.

请参见 http://www.scala-lang .org/api/2.11.5/index.html#scala.Array 了解更多详细信息.

See http://www.scala-lang.org/api/2.11.5/index.html#scala.Array for more details.

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