除法运算给我错误的结果 [英] Division operation is giving me the wrong result

问题描述

我正在尝试在Processing中将一个数除以另一个，而我一直得到错误的答案.

I'm trying to divide one number by another in Processing, and I keep getting the wrong answer.

float a;
a = 3/2;
println(a);

给我

1.0

那么答案应该是1.5.

when then answer should be 1.5.

尝试其他号码，

float a;
a = 2/3;
println(a);

给我

0.0

答案应该是0.666666 ....

when the answer should be 0.666666....

有什么我想念的吗?我查看了处理除法文档，看来我使用的语法正确.

Is there something I'm missing? I looked over the Processing documentation for division and it seems like I'm using the right syntax.

推荐答案

就像其他人说的那样，您正在使用整数除法.

Like others have said, you're using integer division.

请记住，int值不能保留小数位.因此，如果您进行的计算会导致小数位，则这些值会被截断，并且只剩下整数部分(换句话说，就是整数部分) ).

Remember that int values can't hold decimal places. So if you do a calculation that would result in decimal places, those values are truncated and you're left with only the whole number part (in other words, the integer part).

int x = 1;
int y = 2;
int z = x/y; //0

int x = 5;
int y = 2;
int z = x/y; //2

您使用的是 int文字值(如2和3这样的数字)，并且它们没有小数位，因此Processing将它们视为int值，并且它们遵守上述规则.

You're using int literal values (digits like 2 and 3), and those don't have decimal places, so Processing treats them like int values, and they obey the above rules.

如果您关心小数位，则可以将它们存储在float或double变量中:

If you care about the decimal places, then either store them in float or double variables:

float x = 1;
float y = 2;
float z = x/y; //.5

float x = 5;
float y = 2;
float z = x/y; //2.5

或者通过添加小数部分来使用float文字:

Or just use float literals by adding a decimal part:

float a = 2.0/3.0;

处理现在知道这些是float值，因此您将保留小数位.

Processing now knows that these are float values, so you'll keep the decimal places.

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