计算C#中的绝对绝对偏差 [英] Calculating Median Absolute Deviation in C#

问题描述

我需要对一个数字集执行许多统计计算，而我需要计算的内容之一是中位数绝对偏差.我提供了一个ISO标准，它告诉我的只是

I am required to perform a number of statistical calculations on a number set and one of the things I need to calculate is the Median Absolute Deviation. I was supplied with an ISO standard and all it tells me is

我不知道该如何处理该信息，因为我没有进行任何统计数学培训.因此，我无法将以上内容转换为C#函数.

I have no idea what to do with that info as I do not have any statistical math training. As such, I can't translate the above into a C# function.

推荐答案

中位数是 sorted 数组的 middl e元素(如果数组包含偶数项):

Median is a middle element of the sorted array (or average of two middle items if the array has even items):

  double[] source = new double[] { 1, 2, 3, 4, 5 };

  Array.Sort(source);

  double med = source.Length % 2 == 0
    ? (source[source.Length / 2 - 1] + source[source.Length / 2]) / 2.0
    : source[source.Length / 2];

  double[] d = source
    .Select(x => Math.Abs(x - med))
    .OrderBy(x => x)
    .ToArray();

  double MADe = 1.483 * (d.Length % 2 == 0
    ? (d[d.Length / 2 - 1] + d[d.Length / 2]) / 2.0
    : d[d.Length / 2]);

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