我如何获得移动手指的ID [英] How do I get the ID of the moving finger

问题描述

在code下面我测试多点触摸。当第一个手指触摸屏幕时，我得到的手指的ID，如果我也有第二手指触摸屏幕时，我得到的ID为好。但是当我移动手指，我只得到了ID为0，而不是任何的ID 1，第二次手指！我以后需要通过id来存储X和Y坐标的方法，我需要知道的ID在屏幕上绘制。

我如何得到正确的ID为运动？

  @覆盖
公共布尔onTouch（视图V，MotionEvent事件）{
    同步（gameLoop）{
        对（INT I = 0; I＆下; event.getPointerCount（）及＆放大器;我2;我++）{            ID = event.getPointerCount（）;            //检查手指的触摸屏
            如果（event.getActionIndex（）== I和及（event.getActionMasked（）== MotionEvent.ACTION_POINTER_DOWN || event.getActionMasked（）== MotionEvent.ACTION_DOWN））{                INT J = event.getPointerCount（）;
                INT ID = event.getPointerId（ⅰ）;
                字符串numDown = Integer.toString（J）;
                字符串SID = Integer.toString（ID）;
                Log.i（测试，数下来：+ numDown +ID：+ SID）;
            }            //检查手指在屏幕上移动
            如果（event.getActionIndex（）== I和及（event.getActionMasked（）== MotionEvent.ACTION_MOVE））{                INT ID = event.getPointerId（ⅰ）;
                字符串SID = Integer.toString（ID）;
                Log.i（测试，移动ID：+ SID）;
            }            //检查手指离开屏幕
            如果（event.getActionIndex（）== I和及（event.getActionMasked（）== MotionEvent.ACTION_POINTER_UP || event.getActionMasked（）== MotionEvent.ACTION_UP））{                INT K = event.getPointerCount（）;
                INT ID = event.getPointerId（ⅰ）;
                字符串numUp = Integer.toString（K）;
                字符串SID = Integer.toString（ID）;
                Log.i（测试，数了起来：+ numUp +ID：+ SID）;
            }
        }
    }
    返回true;
}
 

解决方案

您并不需要循环

  

公众最终诠释getPointerId（INT pointerIndex）

  
  

指针检索参数pointerIndex生指数。值可以
  从0（第一个指针是向下）getPointerCount（） - 1

先以手指（event.getX（0），event.getY（0））

第二根手指（event.getX（1），event.getY（1））

In the code below I'm testing multi touch. When the first finger touch the screen, I get the ID of that finger and if I also touch the screen with a second finger, I get that ID as well. But When I move the fingers, I only get the ID 0 and not any for ID 1, the second finger! I need to pass the id later to an method that stores the X and Y coordinates and I need to know which ID that draws on the screen.

How do I get the correct ID for the movement?

    @Override
public boolean onTouch(View v, MotionEvent event) {
    synchronized (gameLoop) {
        for (int i = 0; i < event.getPointerCount() && i < 2; i++) {

            id = event.getPointerCount();

            // Check if finger touch screen
            if(event.getActionIndex() == i && (event.getActionMasked() == MotionEvent.ACTION_POINTER_DOWN || event.getActionMasked() == MotionEvent.ACTION_DOWN)) {

                int j = event.getPointerCount();
                int id = event.getPointerId(i);
                String numDown = Integer.toString(j);
                String sId = Integer.toString(id);
                Log.i("Test", "Number DOWN: " + numDown + " ID: " + sId);
            }

            // Check if finger moves on screen
            if(event.getActionIndex() == i && (event.getActionMasked() == MotionEvent.ACTION_MOVE)) {

                int id = event.getPointerId(i);
                String sId = Integer.toString(id);
                Log.i("Test", " Moving ID: " + sId);
            }

            // Check if finger leave screen
            if(event.getActionIndex() == i && (event.getActionMasked() == MotionEvent.ACTION_POINTER_UP || event.getActionMasked() == MotionEvent.ACTION_UP)) {

                int k = event.getPointerCount();
                int id = event.getPointerId(i);
                String numUp = Integer.toString(k);
                String sId = Integer.toString(id);
                Log.i("Test", "Number UP: " + numUp + " ID: " + sId);
            }
        }
    }
    return true;
}

解决方案

You didn't need for-loop

public final int getPointerId (int pointerIndex)

Parameters pointerIndex Raw index of pointer to retrieve. Value may be from 0 (the first pointer that is down) to getPointerCount()-1.

First finger (event.getX(0),event.getY(0))

Second finger (event.getX(1),event.getY(1))

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