如何将矩阵划分为相等的部分? [英] How to divide a matrix into equals parts?

问题描述

假设我有一个100x100的矩阵，我想将其分成10x10的相等部分.

Let's say I have a 100x100 matrix, I want to divide it into equal parts of 10x10.

问题在于输入矩阵可以是任何大小(但始终为mod 10). 我看了mat2cell函数，但对于动态数量的零件，它似乎不起作用. 还是我错过了什么?

The problem is that the input matrix can be of any size (but always mod 10). I looked at the mat2cell function but it does not seem to work for a dynamic number of parts. Or am I missing something?

推荐答案

您只需要确切地告诉mat2cell您希望矩阵如何划分即可.如果您肯定两个方向上的比率总是10的倍数，那么(很)简单.假设X是您要划分的矩阵，并且您想要在Y中生成的单元格数组:

You just have to tell mat2cell exactly how you want the matrix divided up. If you're positive that it is always going to be a multiple of 10 in both directions, then it is (fairly) simple. Assuming that X is the matrix that you want to divide, and you want the resulting cell array in Y:

Y = mat2cell(X, repmat(10,[1 size(X,1)/10]), repmat(10,[1 size(X,2)/10]));

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