如何解决matlab中的散点图错误 [英] how to solve scatterplot error in matlab

问题描述

以下是我正在编写的代码的一部分，

following is a part of the code I am writing,

for ii=1:length(k31)

B   = [k31(ii);k32(ii)];

X=abs( pinv(A)*B);

g1(ii)=X(1,:);

g2(ii)=X(2,:);

g3(ii)=X(3,:);

end

scatter(x(1:end-1), y(1:end-1), 5, g1);

但是我无法绘制数据，错误如下

But I am not able to plot the data, the error is as follows

??? Error using ==> scatter at 79

C must be a single color, a vector the same length as X, or an M-by-3 matrix.

x和y与k31的尺寸相同...但是仍然显示出这样的错误

x and y have the same dimensions as k31...but still it is showing such an error

推荐答案

您正在喂养 scatter ，带有4个参数:scatter(X, Y, S, C).您的错误状态:

You are feeding scatter with 4 arguments: scatter(X, Y, S, C). Your error states:

C必须是单色，长度与X相同的向量或M×3矩阵.

C must be a single color, a vector the same length as X, or an M-by-3 matrix.

表示第四个参数g1与第一个参数的尺寸不同.

meaning that the fourth argument g1 does not have the same dimensions as the first argument.

这里可能发生的是，您没有在循环之前重新初始化g1，因此它保留了先前的大小.将以下行放在for-循环之前:

What probably happened here is that you didn't re-initialize g1 before the loop, and so it retained its previous size. Put the following line before the for-loop:

g1 = zeros(size(k31));

它应该可以工作.

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