使用datestr时如何以1乘1的数组显示日期? [英] How can i display date in a 1 by 1 array when i use datestr?

问题描述

我使用datestr将732154.873773148传输到26-Jul-2004 20:58:14，但是当我将其输出到.csv文件时，它将是一个1*20数组...，但是我想要的是将其存储在1*1数组，我应该怎么办?

I use datestr to transfer 732154.873773148 into 26-Jul-2004 20:58:14, but when i ouput it to a .csv file, it will be an 1*20 array..., but what i want is to store it in a 1*1 array, how should i do?

并且是否存在将26-Jul-2004 20:58:14转换为2004/07/26 20:58:14的简便方法?

And does there exist easy method to transfer 26-Jul-2004 20:58:14 to 2004/07/26 20:58:14?

谢谢:)

data = csvread('4.csv');
date = data(:, 1);
loc = data(:, 2);
record_num = size(loc, 1);

result = zeros(record_num, 2);
new_date = datestr(date);
csvwrite('4_res.txt', new_date);

我想要的是 2004/07/26 20:58:14

但它将是 2,0,0,4,/,0,7,/,2,6, ,2,0,:,5,8,:,1,4

推荐答案

要使日期具有2004/07/26 20:58:14格式，可以使用:

In order to have the date in the format 2004/07/26 20:58:14 you can use:

new_date = datestr(date,'mm/dd/yy HH:MM:SS');

要编写仅包含1x1单元格的csv文件，您可以使用dlmwrite，并将空字符串用作分隔符:

To write a csv file with only a 1x1 cell you can use dlmwrite with the empty string as delimiter :

dlmwrite('4_res.txt',new_date, 'delimiter','')

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