用行数可变的矩阵匹配模式并在Matlab中对它们进行计数 [英] Match patterns in a matrix with a variable number of lines and count them in Matlab

问题描述

我有一个像这样的矩阵:

I have a matrix like this one:

8   
8   
8   
2   
2   
2   
6   
6   
7   
7   
7   
1   
1   
6   
6   
6   
6   
8   
8   
0   
6   
8   
8   
1   
6   
6   

有些固定模式会经常重复.我想检测它们.他们按照以下规则重复进行:

There are fixed patterns that always repeat. I would like to detect them. They repeat according to these rules:

第7行，然后是数字(0、1或2)，然后是6

Lines with 7 followed by lines with a number which can be (0, 1 or 2), followed by a 6

第8行，然后是数字(0、1或2)，然后是6

Lines with 8 followed by lines with a number which can be (0, 1 or 2), followed by a 6

对于检测到的单个模式上的每个值(独立于它们组成的行数)，在第二列中写入等级数，从1开始，每次在第一列中每次增加新模式时都递增被检测到.结果将是:

For each one of the values on a single pattern detected (independently from the number of lines they are composed of), write in a second column a number of rank, starting from 1 and incrementing each time a new pattern in column one is detected. This would be the result:

    8   1
    8   1
    8   1
    2   1
    2   1
    2   1
    6   1
    6   1
    7   2
    7   2
    7   2
    1   2
    1   2
    6   2
    6   2
    6   2
    6   2
    8   3
    8   3
    0   3
    6   3
    8   4
    8   4
    1   4
    6   4
    6   4

第2列在每行中编码第一个模式(一系列值= 1表示这行上有与模式1相关的数据)，第二个模式(值2)，依此类推... 我该怎么办?

Column 2 encodes in each line the first pattern (series of values = 1 meaning that on this line there is data related to patter 1), the second pattern (values 2) and so on... How can I do that?

推荐答案

这里的解决方案仅使用结束标记"将矩阵分成多个部分:

Here's a solution that only uses the "closing tags" to split the matrix into parts:

function b = replaceValues(a)
  closingTag = 6;
  % Find all closing tag positions
  clTagPos = a(:, 1) == closingTag;
  % Keep only the "last" tags and add matrix start/end positions
  splitPoints = [0; find(diff(clTagPos) == -1); length(a)];
  % Split matrix into cell array
  acell = mat2cell(a, diff(splitPoints));
  % Replace the second column of each part with the corresponding non-zero value
  bcell = cellfun(@(c)[c(:, 1) ones(length(c), 1)*c(find(c(:, 2), 1), 2)], acell, 'UniformOutput', 0);
  % Convert back to matrix
  b = cell2mat(bcell);
end

Matlab中的输入输出示例:

Example input-output in Matlab:

a =  

 8     0
 8     0
 8     0
 2     1
 2     1
 2     1
 6     0
 6     0
 7     0
 7     0
 7     0
 1     2
 1     2
 6     0
 6     0
 6     0
 6     0
 8     0
 8     0
 0     3
 6     0
 8     0
 8     0
 1     4
 6     0
 6     0

>> b = replaceValues(a)

b =

 8     1
 8     1
 8     1
 2     1
 2     1
 2     1
 6     1
 6     1
 7     2
 7     2
 7     2
 1     2
 1     2
 6     2
 6     2
 6     2
 6     2
 8     3
 8     3
 0     3
 6     3
 8     4
 8     4
 1     4
 6     4
 6     4

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