给定一个ID从矩阵中删除行-Matlab [英] Delete row from matrix given an id- Matlab

问题描述

如何根据第一列的值从矩阵中删除特定行?

How can I delete a certain row from a matrix depending on the 1st column value?

例如:A=[1 2 3;3 4 5;5 6 7] 其中第一列的值代表ID，我想删除ID为5的行. 我已经知道A(3,:)=[]会删除第三行，但是如果我有ID并且不知道行号怎么办?

For example: A=[1 2 3;3 4 5;5 6 7] where the values of the first column represent the ids and I want to delete the row that has 5 as an id. I already know that A(3,:)=[] deletes the third row, but what if I have the id and don't know the row number?

推荐答案

您可以使用find:

id=5;
A(find(A(:,1)==id),:)=[]
A =

 1     2     3
 3     4     5

请注意，正如 Divakar 所述，由于逻辑索引，您甚至可以省略find:

Note that, as mentioned by Divakar, thanks to logical indexing you can even omit the find:

A(3,:)

和

A(logical([0 0 1]),:)

等价于此

A(find(A(:,1)==id),:)=[]

和

A(A(:,1)==id,:)=[]

将给出相同的结果.

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