如何随机排列单元格数组中的行 [英] How to shuffle the rows in a cell array

问题描述

我有一个带有x列的单元格数组，每列都有一个yx1单元格.我想随机化列中的行".也就是说，对于每个具有元素a_1，a_2，... a_y的yx1单元，我想对a_i的索引应用相同的置换.

I have a cell array with x columns, each with a yx1 cell. I would like to randomize the "rows" within the columns. That is, for each yx1 cell with elements a_1, a_2, ... a_y, I would like to apply the same permutation to the indices of a_i.

我有一个执行此操作的功能，

I've got a function that does this,

function[Oarray] = shuffleCellArray(Iarray);

    len   = length(Iarray{1});
    width = length(Iarray);
    perm  = randperm(len);

    Oarray=cell(width, 0);

    for i=1:width;
        for j=1:len;
            Oarray{i}{j}=Iarray{i}{perm(j)};
        end;
    end;

但是如您所见，它有点难看.有更自然的方法吗?

but as you can see it's a bit ugly. Is there a more natural way to do this?

我意识到我可能使用了错误的数据类型，但是出于遗留原因，我想避免切换.但是，如果答案是切换"，那么我想这就是答案.

I realize that I'm probably using the wrong data type, but for legacy reasons I'd like to avoid switching. But, if the answer is "switch" then I guess that's the answer.

推荐答案

我假设您有一个列向量的单元格数组，例如

I'm assuming you have a cell array of column vectors, such as

Iarray = {(1:5).' (10:10:50).' (100:100:500).'};

在这种情况下，您可以这样操作:

In that case, you could do it this way:

ind = randperm(numel(Iarray{1})); %// random permutation
Oarray = cellfun(@(x) x(ind), Iarray, 'UniformOutput', 0); %// apply that permutation
                                                           %//  to each "column"

或转换为中间矩阵，然后返回至单元格数组:

Or converting to an intermediate matrix and then back to a cell array:

ind = randperm(numel(Iarray{1})); %// random permutation
x = cat(2,Iarray{:}); %// convert to matrix
Oarray = mat2cell(x(ind,:), size(x,1), ones(1,size(x,2))); %// apply permutation to rows
                                                           %// and convert back

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