Android的ImageView的setvisibility [英] android imageview setvisibility

问题描述

我想改变的ImageView的知名度，如果值= X

i want to change visibility of imageview if value= x

但我对日食的错误消息。

but i have error message on eclipse.

下面是我的Java的一部分

here is part of my java

                if (success == 1) {
                    // products found
                    // Getting Array of Products
                    products = json.getJSONArray(TAG_PRODUCTS);

                    // looping through All Products
                    for (int i = 0; i < products.length(); i++) {
                        JSONObject c = products.getJSONObject(i);

                        // Storing each json item in variable
                        String id = c.getString(TAG_PID);
                        String name = c.getString(TAG_NAME);
                        String price = c.getString(TAG_PRICE);
                        String cu = c.getString(TAG_CU);
                        /////////////
                                                ///HERE THE BUG////
                        if (cu == "1"){

                            cu = "oui";
                        }
                        else {  
                            ImageView image_A_wrong = (ImageView) findViewById(R.id.imageView1);
                            image_A_wrong.setVisibility(View.GONE);

                        }

和我在这里的xml文件

and here my xml file

<ImageView
        android:id="@+id/imageView1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:src="@drawable/quo100px"
        android:visibility="gone" />

TKS您的帮助

tks advance for your help

推荐答案

使用 cu.equals（1），而不是铜== 1键，你会没事的。

Use cu.equals("1") rather than cu == "1" and you'll be fine

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