无法使较小的网格线出现在matplotlib图中 [英] Cannot get minor grid lines to appear in matplotlib figure

问题描述

好，所以我有下面的代码，用于实时图形化显示通过串行接收的嵌入式设备中的某些数据.它并不是要成为生产工具，而应该是内部eng工具，因此它并不是非常友好的用户界面.问题是，无论我做什么，即使在此处将它们设置为True, which=both，也无法显示较小的网格线.我可以对主要的网格线做任何我想做的事情，但是未成年人不会出现.有任何想法吗?这是代码:

Ok so I have the code below for real-time graphing some data from an embedded device received over serial. It's not meant to be a production tool but rather an internal eng tool, hence it's not terribly user-friendly. The problem is that no matter what I do, I can't get minor grid lines to appear, even though here they are set to True, which=both. I can do anything I want to the major grid lines but the minors won't appear. Any ideas? Here is the code:

import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation
import serial

SERIAL_PORT_NUM=9

...a bunch of constants...
#windows starts serial port numbers at 1, python starts at 0
SERIAL_PORT_NUM = SERIAL_PORT_NUM - 1
"""
Open the serial port
"""
ser =serial.Serial(port=SERIAL_PORT_NUM,baudrate=115200,bytesize=8,parity='N',stopbits=1,timeout=None,xonxoff=0,rtscts=0)

# First set up the figure, the axis, and the plot element we want to animate
raw_adc_fig = plt.figure()
raw_adc_ax = plt.axes(xlim=(0, 200), ylim=(0, 2047))
raw_adc_ax.grid(True, which='both')
raw_adc_fig.suptitle("Raw ADC data")
plt.ylabel("ADC values (hex)")
plt.xlabel("time (sec)")
raw_adc_line, = raw_adc_ax.plot([], [], lw=2)

def read_serial(serial_port):
    tmp = ''
    same_line = True
    while same_line:
        tmp += serial_port.read(1)
        if tmp != '':
            if tmp[-1] == '*':
                same_line = False
    tmp = tmp.rstrip()
    tmp = tmp.lstrip()
    return tmp

def process_serial(input_data):
    output_data = 0
    intermediate_data = input_data[A_TYPE_START_POS:A_TYPE_STOP_POS + 1]
    if( intermediate_data != ''):
        output_data =  int(intermediate_data , 16 )
    else:
        print "bad data"
        output_data = -100

    return output_data

def get_sound_value(serial_port):
    cur_line = ''

    get_next_line = True
    # read in the next line until a sound packet of type A is found
    while( get_next_line ):
        cur_line = read_serial(serial_port)
        if( (cur_line != '') and (cur_line[0:3] == ROUTER_SOUND_DATA) and (len(cur_line) == D_TYPE_STOP_POS + 2) ):
          get_next_line = False

    sound_value = process_serial(cur_line)
    return sound_value

# initialization function: plot the background of each frame
def raw_adc_init():
    raw_adc_line.set_data([], [])
    return raw_adc_line,

# animation function.  This is called sequentially
def raw_adc_animate(i):
    sound_data_list.append( get_sound_value(ser) )
    y = sound_data_list
    if( len(y) == 190 ):
        del y[0]
    x = np.linspace(0, len(y), len(y))
    raw_adc_line.set_data(x, y)
    return raw_adc_line,

# call the animator.  blit=True means only re-draw the parts that have changed.
raw_adc_anim = animation.FuncAnimation(raw_adc_fig, raw_adc_animate, init_func=raw_adc_init, frames=200, interval=1000, blit=True)

修复了打开串行端口的错误.将timeout=0更改为timeout=None.

fixed a bug in opening the serial port. Changed timeout=0 to timeout=None.

推荐答案

不幸的是，在这方面ax.grid有点令人困惑. (这是一个设计错误/常见问题.)它打开了次网格，但次刻度仍然关闭.

Unfortunately, ax.grid is a bit confusing in this regard. (This is a design bug / common gotcha.) It turns the minor grid on, but the minor ticks are still turned off.

除了调用ax.grid(True, which='both')之外，您还需要调用plt.minorticks_on或ax.minorticks_on.

What you need to do is call plt.minorticks_on or ax.minorticks_on in addition to calling ax.grid(True, which='both').

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