在堆叠的条形图中添加标签 [英] Adding labels to stacked bar chart

问题描述

我正在绘制某些类别中各个办公室的交叉列表.我想放一张水平堆叠的条形图，在其中标记每个办公室及其值.

I'm plotting a cross-tabulation of various offices within certain categories. I'd like to put together a horizontal stacked bar chart where each office and its value is labeled.

下面是一些示例代码:

df = pd.DataFrame({'office1': pd.Series([1,np.nan,np.nan], index=['catA', 'catB', 'catC']),
              'office2': pd.Series([np.nan,8,np.nan], index=['catA', 'catB', 'catC']),
              'office3': pd.Series([12,np.nan,np.nan], index=['catA', 'catB', 'catC']),
              'office4': pd.Series([np.nan,np.nan,3], index=['catA', 'catB', 'catC']),
              'office5': pd.Series([np.nan,5,np.nan], index=['catA', 'catB', 'catC']),
              'office6': pd.Series([np.nan,np.nan,7], index=['catA', 'catB', 'catC']),
              'office7': pd.Series([3,np.nan,np.nan], index=['catA', 'catB', 'catC']),
              'office8': pd.Series([np.nan,np.nan,11], index=['catA', 'catB', 'catC']),
              'office9': pd.Series([np.nan,6,np.nan], index=['catA', 'catB', 'catC']),
              })
ax = df.plot.barh(title="Office Breakdown by Category", legend=False, figsize=(10,7), stacked=True)

这给了我一个很好的起点:

This gives me a fine starting point:

但是，我想要的是:

However, what I'd like to have is this:

经过研究，我想出了以下代码，可以在类别"轴上正确地排列标签:

After some research, I came up with the following code that correctly lines up labels on the 'category' axis:

def annotateBars(row, ax=ax):
    for col in row.index:
        value = row[col]
        if (str(value) != 'nan'):
            ax.text(value/2, labeltonum(row.name), col+","+str(value))

def labeltonum(label):
    if label == 'catA':
        return 0
    elif label == 'catB':
        return 1
    elif label == 'catC':
        return 2

df.apply(annotateBars, ax=ax, axis=1)

但是，这不包括条的堆积".我还尝试了遍历plot命令返回的patches容器(它可以让我检索每个矩形的x和y位置)，但是随后我失去了与办公室标签的任何连接.

But this doesn't factor in the "stacking" of the bars. I've also tried iterating through the patches container returned by the plot command (which can let me retrieve x & y positions of each rectangle), but I then lose any connection to the office labels.

推荐答案

弄清楚了.如果我遍历数据帧每一行的列，则可以建立一个与ax.patches中的矩形进度匹配的标签列表.下面的解决方案:

Figured it out. If I iterate through the columns of each row of the dataframe I can build up a list of the labels I need that matches the progression of the rectangles in ax.patches. Solution below:

labels = []
for j in df.columns:
    for i in df.index:
        label = str(j)+": " + str(df.loc[i][j])
        labels.append(label)

patches = ax.patches

for label, rect in zip(labels, patches):
    width = rect.get_width()
    if width > 0:
        x = rect.get_x()
        y = rect.get_y()
        height = rect.get_height()
        ax.text(x + width/2., y + height/2., label, ha='center', va='center')

添加到上面的代码后，会产生:

Which, when added to the code above, yields:

现在只需要处理太小的条形标签的重新排列...

Now to just deal with re-arranging labels for bars that are too small...

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