打印带有索引的矩阵python [英] print matrix with indicies python

问题描述

我在Python中定义了一个矩阵，如下所示:

I have a matrix in Python defined like this:

matrix = [['A']*4 for i in range(4)]

如何以以下格式打印它:

How do I print it in the following format:

   0  1  2  3
0  A  A  A  A
1  A  A  A  A
2  A  A  A  A
3  A  A  A  A

推荐答案

此函数与您的确切输出匹配.

This function matches your exact output.

>>> def printMatrix(testMatrix):
        print ' ',
        for i in range(len(testMatrix[1])):  # Make it work with non square matrices.
              print i,
        print
        for i, element in enumerate(testMatrix):
              print i, ' '.join(element)
>>> matrix = [['A']*4 for i in range(4)]
>>> printMatrix(matrix)
  0 1 2 3
0 A A A A
1 A A A A
2 A A A A
3 A A A A
>>> matrix = [['A']*6 for i in range(4)]
>>> printMatrix(matrix)
  0 1 2 3 4 5
0 A A A A A A
1 A A A A A A
2 A A A A A A
3 A A A A A A

要检查单个长度的元素并将&替换为长度大于1的元素，可以对列表理解进行检查，代码将更改如下.

To check for single length elements and put an & in place of elements with length > 1, you could put a check in the list comprehension, the code would change as follows.

>>> def printMatrix2(testMatrix):
    print ' ',
    for i in range(len(testmatrix[1])):
        print i,
    print
    for i, element in enumerate(testMatrix):
        print i, ' '.join([elem if len(elem) == 1 else '&' for elem in element])
>>> matrix = [['A']*6 for i in range(4)]
>>> matrix[1][1] = 'AB'
>>> printMatrix(matrix)
  0 1 2 3 4 5
0 A A A A A A
1 A AB A A A A
2 A A A A A A
3 A A A A A A
>>> printMatrix2(matrix)
  0 1 2 3 4 5
0 A A A A A A
1 A & A A A A
2 A A A A A A
3 A A A A A A

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