识别矩阵中的值 [英] Identifying value in matrix

问题描述

我遇到问题，然后需要您的帮助来解决.

I have a problem and then I need your help to solve it.

我有一个矩阵A

A = [ 0 0 1 2 3 4 0;
      1 2 3 4 0 0 0;
      0 0 0 1 2 3 4;
      0 1 2 3 4 0 0]

然后我想知道矩阵A中每行的每个值"1"有多少个，不在同一列中，矩阵A中每行的每个值> = 3".

and then I want to know how many number of each values "1" of each rows in matrix A which is not in the same column with each value ">=3" of each rows in matrix A.

所以我希望我的回答

Ans = 2

谢谢.

推荐答案

尝试一下:

>> num = sum( any(A(:,all(A<3))==1,2) )
num =
     2

首先，我们找到不包含大于或等于3 idx = all(A<3)的值的列索引.

First we find the columns indices containing no values greater or equal to 3 idx = all(A<3).

接下来在这些列A(:,idx)中，我们找到包含任意1的行:any(A(:,idx)==1,2).

Next in those columns A(:,idx), we find the rows containing any 1: any(A(:,idx)==1,2).

最后，我们计算发现了多少这样的行sum(.)

Finally we count how many such rows were found sum(.)

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