如何计算矩阵的以2为底的对数? [英] How to calculate the base 2 log of a matrix?

问题描述

我发现的唯一计算矩阵而不是矩阵每个对数的对数的函数是scipy的

The only function that I found that calculates the log of the matrix, and not of each component of the matrix, was scipy's logm() function, but it finds the log with base e, I need the base 2 log.

推荐答案

您可以使用基数更改公式来转换对数的底数:

You can use the change-of-base formula to convert the base of the logarithm:

log2(x) = logm(x) / logm(2)

Mathematica StackExchange对此背后的数学进行了更深入的讨论:

Mathematica StackExchange has some more in depth discussion of the math behind this:

https://mathematica.stackexchange.com/a/92293

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