如何将3D矩阵逆时针旋转90度? [英] How do I rotate a 3D matrix by 90 degrees counterclockwise?

问题描述

在Java中，我试图将矩阵逆时针旋转90度.我找到了有关如何使用2D矩阵执行此操作的答案，但我的矩阵是3D.

I'm trying to rotate a matrix counterclockwise by 90 degrees in Java. I found answers on how to do this with a 2D matrix, but my matrix is 3D.

这是我发现如何进行2D旋转的方法:

Here's how I found out on how to do a 2D rotation:

static int[][] rotateCW(int[][] mat) {
    final int M = mat.length;
    final int N = mat[0].length;
    int[][] ret = new int[N][M];
    for (int r = 0; r < M; r++) {
        for (int c = 0; c < N; c++) {
            ret[c][M-1-r] = mat[r][c];
        }
    }
    return ret;
}

那我该如何旋转3D矩阵?

How would I go about rotating a 3D matrix then?

推荐答案

通过将矩阵乘以旋转矩阵

x轴的基本矩阵是:

        | 1     0      0    |
Rx(a) = | 0  cos(a) -sin(a) |
        | 0  sin(a)  cos(a) |

对于90度，只需将cos(90)= 0和sin(90)= 1设置为:

For 90 degrees simply set cos(90) = 0 and sin(90) = 1 which should lead to:

        | 1     0      0    |
Rx(a) = | 0     0     -1    |
        | 0     1      0    |

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