将R中的整数矩阵保留为整数矩阵 [英] Keep Integer Matrix in R as Integer Matrix

问题描述

假设我在R中有一个用"1"填充的整数矩阵.

Suppose that I have an integer matrix in R filled with "1".

当我将其除以2时，它将转换为双精度矩阵.

When I divide it by two it will be converted to a double matrix.

如何强制R不更改类型矩阵? (因此矩阵将以0代替.5填充.)

How can I force R to not change the type matrix? (So the matrix will be filled with 0 instead of .5).

的确可以稍后再使用round函数，但这会大大降低速度.

It is true that I can use round function later, but it decrease the speed significantly.

推荐答案

您可以使用欧几里得除法%/%，并确保除以2L，而不是2.

You can use Euclidian division, %/%, and make sure you divide by 2L, not 2.

x <- matrix(1L, 5, 5)
str( x %/% 2L )
# int [1:5, 1:5] 0 0 0 0 0 0 0 0 0 0 ...

这篇关于将R中的整数矩阵保留为整数矩阵的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！