如何在朗姆酒时间从Java文件将值传递给Maven pom.xml? [英] How to pass value to maven pom.xml at rum time from java file?

问题描述

我有一个Java文件，其中的变量在运行时取值.我使用Web服务发现来搜索服务并将其URL保留在变量中. 现在，我需要将此值传递给pom.xml.

I have a java file where a variable taken value at run time.I search for a service using web service discovery and keep its url in a variable. Now I need to pass this value to pom.xml.

abc.java的代码为

abc.java has code with

String url= http://xx.xx.xx.xx:55939/ABCDevice?wsdl

Pom.xml是:

<wsdlOptions>
           <wsdlOption>
           <wsdl>url</wsdl> <!-- get urlvalue from java file -->
            <wsdlLocation>classpath:com/admin/discovery/ABCService.wsdl
                </wsdlLocation>
            </wsdlOption>
            </wsdlOptions>

在wsdl中，我想传递字符串值" http://xx.xx.xx .xx:55939/ABCDevice?wsdl "，只有在运行时才能确定.

In wsdl i want to pass string value "http://xx.xx.xx.xx:55939/ABCDevice?wsdl" which is determined only after run time.

我该怎么办?

推荐答案

我不认为这是Apache Maven的特定问题，而是一般的Java问题(Maven可能使您意识到了). 在构建期间，您不知道该使用什么url.根据应用程序的类型，您有几种选择:

I don't consider this as an Apache Maven specific issue, but a general Java issue (Maven probably made you aware of it). During build-time you have no idea what the url should be. Depending on the type of application you have several options:

• JNDI(如果是Web容器)
• 预定义位置上的属性文件
• 系统属性
• 作为参数(如果是可执行jar)
• 在部署之前调整web.xml(某些Web容器可以帮助您解决此问题)
• ...

在使用像Spring这样的框架时，可以通过简单的方法来注入上面的选项之一.

In you use a framework like Spring there are easy ways to inject one the options above.

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