如何强制Maven EAR插件在application.xml中使用上下文根变量? [英] How can I force the Maven EAR plugin to use a context root variable within application.xml?

问题描述

我正在使用Maven EAR插件生成包含WAR的EAR的application.xml.

I'm using the Maven EAR plugin to generate the application.xml of my EAR, which contains a WAR.

我希望在运行时确定WAR的contextRoot(这要归功于JBoss AS 7)，因此application.xml应该包含以下内容:

I want the contextRoot of that WAR to be determined at runtime (this works thanks to JBoss AS 7), so the application.xml should contain something like this:

<module>
  <web>
    <web-uri>my.war</web-uri>
    <context-root>${my.context.root}</context-root>
  </web>
</module>

这可以通过在JBoss AS 7中设置系统属性my.context.root并配置JBoss来替换XML描述符文件中的变量来实现:

This works by setting the System Property my.context.root within JBoss AS 7 and configuring JBoss to replace variables within XML descriptor files:

<system-properties>
    <property name="my.context.root" value="/foo"/>
</system-properties>

<subsystem xmlns="urn:jboss:domain:ee:1.1">
  <spec-descriptor-property-replacement>true</spec-descriptor-property-replacement>
  <jboss-descriptor-property-replacement>true</jboss-descriptor-property-replacement>
</subsystem>

如果我通过在EAR中编辑生成的application.xml来执行此操作，那么它将起作用.

If I do this by editing the generated application.xml in the EAR, it works.

但是，我无法让Maven将${my.context.root}写入application.xml中的上下文根.

However, I can't get Maven to write ${my.context.root} into the context root within application.xml.

我首先尝试了此操作(因为没有过滤任何内容，所以应该可以使用):

I tried this first (since nothing is filtered, it should work):

<configuration>
  <modules>
    <webModule>
      <groupId>my.group</groupId>
      <artifactId>my-war</artifactId>
      <contextRoot>${my.context.root}</contextRoot>
    </webModule>
  </modules>
</configuration>

显然，即使filtering默认为false，Maven仍然认为应将其用作Maven属性.结果是EAR插件仅输入WAR的名称:

Apparently, even though filtering defaults to false, Maven still thinks it should use this as Maven property. The result is that the EAR plugin just puts in the WAR's name:

<module>
  <web>
    <web-uri>my-war.war</web-uri>
    <context-root>/my-war</context-root>
  </web>
</module>

所以我尝试了转义:

<configuration>
  <modules>
    <webModule>
      <groupId>my.group</groupId>
      <artifactId>my-war</artifactId>
      <contextRoot>\${my.context.root}</contextRoot>
    </webModule>
  </modules>
</configuration>

然后从字面上看:

<module>
  <web>
    <web-uri>my-war.war</web-uri>
    <context-root>\${my.context.root}</context-root>
  </web>
</module>

我怎样才能让Maven做我想做的事情? (当然，我可以尝试使用Maven替换器插件来破解application.xml，但这很丑...)

How can I get Maven to do what I want? (Of course, I could try to hack application.xml by using the Maven replacer plugin, but that's ugly...)

感谢任何提示！

推荐答案

好吧，因为没人知道更好的答案，所以这是我将application.xml砍成形状的方法:

Well, since nobody knows a better answer, here's how I hacked application.xml into shape:

<plugin>
  <groupId>com.google.code.maven-replacer-plugin</groupId>
  <artifactId>replacer</artifactId>
  <executions>
    <execution>
      <id>replace-escaped-context-root</id>
      <phase>process-resources</phase>
      <goals>
        <goal>replace</goal>
      </goals>
      <configuration>
        <file>${project.build.directory}/${project.build.finalName}/META-INF/application.xml</file>
        <regex>false</regex>
        <token>\${</token>
        <value>${</value>
      </configuration>
    </execution>
  </executions>
</plugin>

<plugin>
  <artifactId>maven-ear-plugin</artifactId>
  <configuration>
    <modules>
      <webModule>
        <groupId>my.group</groupId>
        <artifactId>my-war</artifactId>
        <contextRoot>\${my.context.root}</contextRoot>
      </webModule>
    </modules>
  </configuration>
</plugin>

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