Python查找列表的最小最大值和平均值(数组) [英] Python find min max and average of a list (array)
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问题描述
我很难找出如何从列表中查找分钟 例如
I am having hard time to figure out how to find min from a list for example
somelist = [1,12,2,53,23,6,17]
如何通过定义(def
)函数来查找此列表的最小值和最大值
how can I find min and max of this list with defining (def
) a function
我不想使用内置功能min
推荐答案
from __future__ import division
somelist = [1,12,2,53,23,6,17]
max_value = max(somelist)
min_value = min(somelist)
avg_value = 0 if len(somelist) == 0 else sum(somelist)/len(somelist)
如果要手动查找最小值作为函数:
If you want to manually find the minimum as a function:
somelist = [1,12,2,53,23,6,17]
def my_min_function(somelist):
min_value = None
for value in somelist:
if not min_value:
min_value = value
elif value < min_value:
min_value = value
return min_value
Python 3.4引入了 statistics
软件包,该软件包提供了
Python 3.4 introduced the statistics
package, which provides mean
and additional stats:
from statistics import mean, median
somelist = [1,12,2,53,23,6,17]
avg_value = mean(somelist)
median_value = median(somelist)
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