Gnuplot:最多绘制两个文件 [英] Gnuplot: plotting the maximum of two files

问题描述

假设我有两个这样格式化的文件:
x --- y
0 --- 2
1-2.4
2 --- 3.6
y的值不同. 有没有一种方法可以绘制单个图，即对于每个x，两个文件之间的y的最大值?

邓诺(Dunno)不能很好地解释我的自我.

我正在尝试使用条件语句，但是找不到任何可让我搜索2个不同文件的表达式

解决方案

仅使用gnuplot无法将两个或多个文件合并在一个图中.您必须使用外部工具来执行此操作，例如命令行实用程序paste:

max(x, y) = (x > y ? x : y)
plot '< paste fileA.txt fileB.txt' using 1:(max($2, $4))

y值包含在第二列和第四列中.

下一个版本使用python脚本和numpy来串联文件，但是其他任何脚本语言也可以:

 """paste.py: merge lines of two files."""
import numpy as np
import sys

if (len(sys.argv) < 3):
    raise RuntimeError('Need two files')

A = np.loadtxt(sys.argv[1])
B = np.loadtxt(sys.argv[2])

np.savetxt(sys.stdout, np.c_[A, B], delimiter='\t')
 

要绘制，请使用:

max(x, y) = (x > y ? x : y)
plot '< python paste.py fileA.txt fileB.txt' using 1:(max($2, $4))

let's assume I have two files formatted like this:
x --- y
0 --- 2
1 --- 2.4
2 --- 3.6
which differ for the values of y. is there a way to plot a single graph that is, for every x, the maximum value of y between the two files?

Dunno if explained my self sufficiently well.

I was trying with conditional sentences but I couldn't find any expression that let me search in 2 different files

解决方案

There is no way to combine two files or more in a single plot with gnuplot only. You must use an external tool to do this, e.g. the command line utility paste:

max(x, y) = (x > y ? x : y)
plot '< paste fileA.txt fileB.txt' using 1:(max($2, $4))

The y values are contained in the second and fourth columns.

This next version uses a python script with numpy to concatenate the files, but any other scripting language would also do:

"""paste.py: merge lines of two files."""
import numpy as np
import sys

if (len(sys.argv) < 3):
    raise RuntimeError('Need two files')

A = np.loadtxt(sys.argv[1])
B = np.loadtxt(sys.argv[2])

np.savetxt(sys.stdout, np.c_[A, B], delimiter='\t')

To plot, use:

max(x, y) = (x > y ? x : y)
plot '< python paste.py fileA.txt fileB.txt' using 1:(max($2, $4))

这篇关于Gnuplot:最多绘制两个文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！