在MySQL中查找ID最大值的行 [英] Find row with maximum value of id in MySQL

问题描述

看看下面称为"Articles"的MySQL表:

Take a look at the MySQL table below called "Articles":

+----+-----------+---------+------------------------+--------------------------+
| id | articleId | version | title                  | content                  |
+----+-----------+---------+------------------------+--------------------------+
|  1 |         1 | 0.0     | ArticleNo.1 title v0.0 | ArticleNo.1 content v0.0 |
|  2 |         1 | 1.0     | ArticleNo.1 title v1.0 | ArticleNo.1 content v1.0 |
|  3 |         1 | 1.5     | ArticleNo.1 title v1.5 | ArticleNo.1 content v1.5 |
|  4 |         1 | 2.0     | ArticleNo.1 title v2.0 | ArticleNo.1 content v2.0 |
|  5 |         2 | 1.0     | ArticleNo.2 title v1.0 | ArticleNo.2 content v1.0 |
|  6 |         2 | 2.0     | ArticleNo.2 title v2.0 | ArticleNo.2 content v2.0 |
+----+-----------+---------+------------------------+--------------------------+

我试图提出一个查询以返回Articles.id，其中Articles.version是最大数量.

Im trying to come up with a query to return Articles.id where Articles.version is the maximum number.

实际的Articles表包含10,000多个条目.

The actual Articles table contains over 10,000 entries.

因此，在此示例中，我仅希望返回Articles.id 4和6. 我一直在关注关键字distinct和函数max()，但似乎无法理解它.

So in this example I ONLY want Articles.id 4 and 6 to be returned. Ive been looking at keyword distinct and function max() but cant seem to nail it.

任何建议表示赞赏...

Any suggestions appreciated...

推荐答案

您需要在此处进行子查询:

You need a sub query here:

SELECT a.id, a.version
FROM articles a
WHERE a.version = (
    SELECT MAX(version)
    FROM articles b
    WHERE b.articleId = a.articleId
)

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