使用Python min()max()避免数字的字典顺序 [英] Avoid lexicographic ordering of numerical values with Python min() max()
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问题描述
我有一个脚本可以从一组值中提取随机数.但是,它今天中断了,因为min()
和max()
按字典顺序对值进行排序(因此200被认为大于10000).我如何在这里避免按字典顺序排序? Len
键在正确的轨道上,但不太正确.我找不到其他有帮助的键.
I have a script to pull random numbers from a set of values. However, it broke today because min()
and max()
sort values by lexicographic order (so 200 is considered greater than 10000). How can I avoid lexicographic order here? Len
key is on the right track but not quite right. I couldn't find any other key(s) that would help.
data_set = 1600.csv, 2405.csv, 6800.csv, 10000.csv, 21005.csv
第一次尝试:
highest_value = os.path.splitext(max(data_set))[0]
lowest_value = os.path.splitext(min(data_set))[0]
返回:lowest_value = 10000
highest_value = 6800
第二次尝试:
highest_value = os.path.splitext(max(data_set,key=len))[0]
lowest_value = os.path.splitext(min(data_set,key=len))[0]
返回:lowest_value = 1600
highest_value = 10000
谢谢.
推荐答案
您可以使用key
按文件的数字部分进行排序:
You can use key
to order by the numeric part of the file:
data_set = ['1600.csv', '2405.csv', '6800.csv', '10000.csv', '21005.csv']
highest = max(data_set, key=lambda x: int(x.split('.')[0]))
lowest = min(data_set, key=lambda x: int(x.split('.')[0]))
print(highest) # >> 21005.csv
print(lowest) # >> 1600.csv
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