如何获取char数组中元素的地址? [英] How do I get the address of elements in a char array?

问题描述

我有一个char数组，我需要获取每个元素的地址.

I have a char array and I need to get the address of each element.

cout << &charArray

给我一​​个有效的地址，但是，如果我尝试获取特定元素的地址，则会吐出垃圾:

gives me a valid address, However if I try to get the address of a specific element, it spits out garbage:

cout << &charArray[0]

推荐答案

std::cout << (void*) &charArray[0];

对于char*，有一个operator<<的重载，它试图打印以nul结尾的字符串，该字符串认为您的指针指向其第一个字符.但是并不是所有的char数组都是以nul结尾的字符串，因此是垃圾.

There's an overload of operator<< for char*, that tries to print the nul-terminated string that it thinks your pointer points to the first character of. But not all char arrays are nul-terminated strings, hence the garbage.

这篇关于如何获取char数组中元素的地址?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！