删除指针数组与删除指针向量 [英] Deleting an array of pointers vs deleting a vector of pointers

问题描述

当我们打电话

delete[] array; // array is a pointer to an array

或

delete[] vector; // vector is a pointer to a vector

假定它们是链接列表头指针的数组/向量:这2条语句是否为它们中的每个项目调用析构函数?还是我们应该遍历它们，删除每个项目，然后delete []数组或向量本身?

Assuming these are array/vector of linked list head pointers: Do these 2 statements call the destructors for every item in them? Or should we loop through them, delete each item and then delete[] the array or vector itself?

让我更具体一点， 如果该数组包含一个带有其析构函数的头指针，则它将删除其下一个节点或它指向的节点.

Let me be more specific, If the array holds a head pointer with its destructor is called it deletes its next node or that it points to.

推荐答案

您的第二个代码段不正确. delete和delete[]是两个不同的运算符. delete用于删除由new创建的实例，而delete[]用于删除由new[]创建的元素数组.

Your second code snippet is incorrect. delete and delete[] are two different operators. delete is for delete an instance created by new and delete[] is for delete an array of elements created by new[].

在C ++中，数组和向量不关心它们存储的内容.对于数组和向量，都需要先删除每个项目(如果它们是使用new分配的)，然后再删除数组和向量.

In C++, arrays and vectors does not care about what they store. For both array and vector, you need to delete each item (if they were allocated using new) before deleting the array and the vector.

如果您这样创建数组

Sample* arr[100];
for (int i = 0; i < 100; ++i) {
    arr[i] = new Sample();
}

您需要像这样删除它们

for (int i = 0; i < 100; ++i) {
    delete arr[i];
}

如果您创建这样的向量

vector<Sample*> arr;
for (int i = 0; i < 100; ++i) {
    arr.push_back(new Sample());
}

您需要像这样删除

for (int i = 0; i < 100; ++i) {
    delete arr[i];
}

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