递归setTimeout是否会导致堆栈信息内存泄漏? [英] Does a recursive setTimeout cause a stack info memory leak?

问题描述

我有以下情况:

let func = () => {
  //...
  let id = setTimeout(() => {
    console.trace();
    clearTimeout(id);
    func();
  }, 2000);
}

func();

尽管我读到清除超时句柄将释放用于关闭的内存和处理程序本身，但我仍然很好奇堆栈信息是否可能泄漏.我故意放下console.trace()调用，看起来堆栈信息会无限期地增长.这不是问题吗?我知道它不是在类似递归的堆栈上，在那里我们可能会遇到堆栈大小异常，但是我仍然担心堆栈信息会不断增长.

Although I read that clearing the timeout handle will release the memory for closures and the handler itself, I am still curious if there might be a possible leak in stack information. I put the console.trace() call on purpose and it looks like the stack information grows indefinitely. Isn't that a concern? I know that it is not on a recursive-like stack where we might get a stack size exception but I'm still concerned about the stack information that keeps growing.

推荐答案

否.当func完成执行时，堆栈展开.

No. When func finishes execution, the stack unwinds.

如果func是递归的，则堆栈将如下所示:

If func would be recursive, the stack would look like:

   [init] -> func -> func -> func -> func -> func -> .... 

对于您而言，它是:

  [init] -> func -> setTimeout
       <----     <----

  [timer] -> func -> setTimeout
      <----      <----

  [timer] -> func -> setTimeout
      <----      <----

  ...

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