普通防爆pression更换用空格非字母字符 [英] Regular Expression to replace non alpha characters with spaces

问题描述

我一直在试图建立一个正规的前pression但一直没能得到一个特定的条件下工作。

I have been trying to build a regular expression but haven't been able to get one specific condition to work.

我希望有一个正则表达式删除所有非字母字符，除破折号（ - ）。破折号应该只有当他们都用空格pfixed $ P $所取代。

I want a regex to remove all non alpha characters with the exception of dash (-). Dashes should only be replaced if they are prefixed by a space.

即

TEST-TEST -TEST#TEST.TEST

应改为

TEST-TEST TEST TEST TEST

我一直在使用 [^ A-ZA-Z0-9] 但一直没能包括一个或条件初始化。

I had been using [^a-zA-Z0-9] but haven't been able to include one OR condition init.

推荐答案

下面是我想出了（\ S-| [^ A-ZA-Z0-9 - ]） ...这将删除所有非字母数字，但保留 - 除非有收到了空间 -

Here is what I came up with (\s-|[^A-Za-z0-9-])... It will remove all non alphanumerics but keep the "-" except if there is a space before it " -"

测试使用sed在Linux中，此刻我没有访问VS或单声道，以测试在C＃

Test using sed in Linux, at the moment I don't have access to VS or Mono to test in C#

echo "TEST-TEST -TEST#TEST.TEST -1234" | sed 's/\(\s-\|[^A-Za-z0-9-]\)/ /g'

输出

TEST-TEST TEST TEST TEST 1234

• （）和|用于OR条件
使用 \ S -
• 我们首先删除所有 -
• 接下来我们把所有字母数字和 - 与 [^ A-ZA-Z0-9 - ]
• () and | are used for the OR condition
• We first remove all " -" using \s-
• next we keep all alphanumerics and "-" with [^A-Za-z0-9-]

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