如何使用xslt合并两个xml文件以生成文本输出 [英] How to merge two xml files using xslt generating text output

问题描述

我已经在下面看到了我的问题的变体 how-to-merge-two-xml-files-with-xslt 或者 how-can-i-merge-these-two- xml-files-using-xslt ，但是这些示例不处理文本输出，也不处理对'default.xml'的静态引用.

I already saw variants of my problem under how-to-merge-two-xml-files-with-xslt or how-can-i-merge-these-two-xml-files-using-xslt , but these examples do not handle the text-output and also not handle a static refernece to'default.xml'.

我正在尝试生成由defaults.xml生成的C头文件，该文件由target.xml进行了修改.

I am trying to generate a C headerfile beeing generated from a defaults.xml that gets amended by an target.xml.

我将xsltproc用作xslt处理器，并且希望能够 xslproc merg.xsl target1.xml > target1.h.

I am using xsltproc as xslt processor and would like to be able to do xslproc merg.xsl target1.xml > target1.h.

意味着有一个defaults.xml文件和不同的target.xml文件

Meaning to have one defaults.xml file and different target.xml files

示例defaults.xml:

example defaults.xml:

<?xml version="1.0" encoding="UTF-8"?>

<defaults>
<ConfigParam name="F_SAMPLE_STRING">
  <value>{1,0,0}</value>
</ConfigParam>

<ConfigParam name="F_SAMPLE_INT">
  <value>40</value>
</ConfigParam>

<ConfigParam name="F_SAMPLE_X">
  <value>TRUE_DEF</value>
</ConfigParam>

</defaults>

和一个样本target1.xml

and a sample target1.xml

<?xml version="1.0" encoding="UTF-8"?>
<Override>
		<ConfigParam name="F_SAMPLE_STRING">
		  <value>"hallo"</value>
		</ConfigParam>

		<ConfigParam name="F_SAMPLE_Y">
		  <value>TRUE</value>
		</ConfigParam>
</Override>

我自己的起始xslt看起来像这样，但是确实缺少合并/修改部分

My own starting xslt looks like this, but does lack the merging/amendment part

<?xml version="1.0"?>

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="text"/> 
<xsl:param name="fileName" select=" 'defaults.xml' " />
<xsl:param name="defaults" select="document($fileName)" />
<xsl:variable name="defaultParams" select="$defaults//ConfigParam" />


  <xsl:template match="@* | node() ">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>
  
  
  <xsl:template match="ConfigParam">
  #define <xsl:value-of select="@name"/><xsl:text> </xsl:text><xsl:value-of select="value"/>    <xsl:text>&#xd;&#xa;</xsl:text> 
  </xsl:template>

</xsl:stylesheet>

我看到的其他示例使用静态target.xml或从静态位置使用两个文件(目标/默认值).它们也不输出文本，而是xml. 我是xslt的新手，无法提出良好的合并身份模式. 请帮忙.

The other examples I saw use a static target.xml or use both files (target/defaults) from static locations. They also do not output text but xml. I am new to xslt and can not come up with a good merging identity pattern. Please help.

推荐答案

如果我理解正确，则想这样做:

If I understand correctly, you want to do:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/> 
<xsl:strip-space elements="*"/>

<xsl:param name="path-to-defaults" select="'defaults.xml'" />
<xsl:variable name="defaults" select="document($path-to-defaults)/defaults/ConfigParam" />
<xsl:variable name="overrides" select="/Override/ConfigParam" />

<xsl:template match="/">
    <xsl:apply-templates select="$defaults[not(@name = $overrides/@name)]" />
    <xsl:apply-templates select="$overrides" />
</xsl:template>     

<xsl:template match="ConfigParam">
    <xsl:text>#define </xsl:text>
    <xsl:value-of select="@name"/>
    <xsl:text> </xsl:text>
    <xsl:value-of select="value"/>
    <xsl:text>&#xd;&#xa;</xsl:text> 
</xsl:template>  

</xsl:stylesheet>

这假定您将处理target1.xml文件并指向常量defaults.xml文件.结果是:

This assumes you will be processing the target1.xml file and pointing to a constant defaults.xml file. The result here is:

#define F_SAMPLE_INT 40
#define F_SAMPLE_X TRUE_DEF
#define F_SAMPLE_STRING "hallo"
#define F_SAMPLE_Y TRUE

注意:对于文本输出，您不想使用身份转换模板.

Note: with a text output, you don't want to use the identity transform template.

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