需要了解__init__,__new__和__call__的流程 [英] need to understand the flow of __init__, __new__ and __call__
问题描述
class Singleton(type):
def __init__(self, *args, **kwargs):
print 'calling __init__ of Singleton class', self
print 'args: ', args
print 'kwargs: ', kwargs
super(Singleton, self).__init__(*args, **kwargs)
self.__instance = None
def __call__(self, *args, **kwargs):
print 'running __call__ of Singleton', self
print 'args: ', args
print 'kwargs: ', kwargs, '\n\n'
if self.__instance is None:
self.__instance = super(Singleton, self).__call__(*args, **kwargs)
return self.__instance
class A(object):
__metaclass__ = Singleton
def __init__(self,a):
print 'in __init__ of A: ', self
self.a = a
print 'self.a: ', self.a
a=A(10)
b=A(20)
我从Ben对问题 Python对__new__和__init__的使用中复制了这段代码? 并对其进行了一些修改.但是,我不知道流程.尽管我从更高的层次上了解了此代码的用途.但是,从内部来看,我不太确定.
I copied this code from Ben's answer to the question Python's use of __new__ and __init__? and modified it a little. But, I am not aware of the flow. Although I understand from a higher level what this code is intended to do. But, internally how it works, I am not quite sure of.
运行此代码时,我得到以下输出:-
I get the following output when running this code:-
calling __init__ of Singleton class <class '__main__.A'>
args: ('A', (<type 'object'>,), {'__module__': '__main__', '__metaclass__': <class '__main__.Singleton'>, '__init__': <function __init__ at 0x01F9F7B0>})
kwargs: {}
running __call__ of Singleton <class '__main__.A'>
args: (10,)
kwargs: {}
in __init__ of A: <__main__.A object at 0x01FA7A10>
self.a: 10
running __call__ of Singleton <class '__main__.A'>
args: (20,)
kwargs: {}
我无法理解__init__
和__call__
的args
和kwargs
如何变得不同.
使用元类时,此链接(什么是Python中的元类?)具有解释了如何使用__new__
和一个函数作为元类.但是,我不了解__call__
的使用方式.
I cant understand how the args
and kwargs
for __init__
and __call__
become different.
While using metaclasses, this link (What is a metaclass in Python?) has explained how to use __new__
and a function as a metaclass. But, I do not understand how __call__
is being used.
有人可以解释流程吗?我的意思是说,__new__
,__call__
,__init__
被调用的优先级以及谁调用它们?
Can somebody explain the flow? By this, I mean, the precedence in which __new__
, __call__
, __init__
are called and who calls them?
推荐答案
您的代码不包含任何__new__
,因此对此一无所知.
Your code doesn't include any __new__
, so little can be said about it.
但是您创建一个元类,该元类在创建类A
时实例化.换句话说,类A
本身就是对象,因此是其元类Singleton
的实例.
But you create a metaclass which is instantiated at the time class A
is created. In other words, the class A
is an object itself and as such an instance of its metaclass Singleton
.
让我们看看会发生什么:
So let's look what happens:
A
的环境完成后(其方法存在,其dict也存在,...),该类被创建为元类的实例.本质上,呼叫是
After A
's environment is finished (its methods exist, its dict exists as well, ...), the class gets created as an instance of the metaclass. Essentially, the call is
A = Singleton('A', (object,), <the dict>)
其中<the dict>
是包含类名称空间(此处为__module__
,__metaclass__
和__init__
)的字典.
where <the dict>
is the dict containing the class's namespace (here: __module__
, __metaclass__
and __init__
).
在对此Singleton
的调用上,调用super(Singleton, self).__call__(*args, **kwargs)
会导致调用__new__
方法,该方法返回一个新实例,此后将在该实例上调用.__init__
.
On this call to Singleton
, calling super(Singleton, self).__call__(*args, **kwargs)
results in calling the __new__
method which returns a new instance, on which .__init__
is called afterwards.
这就是为什么发生这种情况:
That's why this happens:
calling __init__ of Singleton class <class '__main__.A'>
args: ('A', (<type 'object'>,), {'__module__': '__main__', '__metaclass__': <class '__main__.Singleton'>, '__init__': <function __init__ at 0x01F9F7B0>})
kwargs: {}
构造A
后,可以通过实例化它来使用它:
After A
is constructed, you use it by instantiating it:
a = A(10)
这将调用A
. A
是Singleton
的实例,因此会调用Singleton.__call__
.效果如下:
This calls A
. A
is an instance of Singleton
, so Singleton.__call__
is invoked – with the effect you see:
running __call__ of Singleton <class '__main__.A'>
args: (10,)
kwargs: {}
Singleton.__call__
调用type.__call__
,这调用A.__new__
和A.__init__
:
in __init__ of A: <__main__.A object at 0x01FA7A10>
self.a: 10
那你做
b = A(20)
调用Singleton.__call__
:
running __call__ of Singleton <class '__main__.A'>
args: (20,)
kwargs: {}
在这里super
调用被禁止,并且旧对象被返回.
Here the super
call is suppressed and the old object is returned.
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