如何提取“编码人"?从mp3元数据使用Python? [英] How to extract "Encoded by" from mp3 metadata using Python?

问题描述

我正在尝试编写Python脚本以从某些mp3文件中提取元数据标签.具体来说，我想提取专辑"和编码人"，如果我右键单击文件并查看详细信息，这些文件将可用:

I am trying to write a Python script to extract metadata tags from some mp3 files. Specifically, I am looking to extract "Album" and "Encoded by", which are available if I right-click on the files and look under details:

我目前正在使用 eyeD3 库来解析元数据.我之所以使用这个库，是因为我认为它可以轻松完成我的任务，但我并不嫁给它.

I am using currently using the eyeD3 library to parse metadata. I am using this library because I thought it would easily accomplish my task, but I am not married to it.

我能够很容易地提取专辑"，但不能提取编码人"字段.如果我打印了所有歌曲标签，则看不到所需的编码人"字段.有什么想法吗?

I am able to extract the "Album" easily enough, but not the "Encoded by" field. If I print out all the song tags, I do not see anything like the "Encoded by" field I need. Any ideas, please?

这是我的代码:

import eyed3

def main():
    music_file = r'G:\Music Collection\54-40\Sweeter Things A Compilation\01 Miss You - 54-40.mp3'

    audiofile = eyed3.load(music_file)
    for attribute_name in dir(audiofile.tag):
        attribute_value = getattr(audiofile.tag, attribute_name)
        print attribute_name, attribute_value

if __name__ == "__main__":
    main()
    print 'done'

推荐答案

事实证明，编码为"字段埋在frame_set对象返回的列表中:audiofile.tag.frame_set['TENC'][0].text

It turns out the "Encoded by" field is buried in a list returned by the frame_set object: audiofile.tag.frame_set['TENC'][0].text

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